i can't understand how Array.join works if separator is an array in Javascript ? I find a detail explanation how it works. My example below
arr1 = ['a','b','c'];
arr2 = ['d', 'e', 'f'];
arr1.join(arr2);
//Output
"ad,e,fbd,e,fc"
2 Answers
The join method accepts a separator and you're passing an array as separator. So, the join method will first transform it to a string: 'd,e,f'
Thus,
ad,e,f
bd,e,f
c // last remains same - no join
// as you may do like ['a','b','c'].join('-') results a-b-c
And final result:
ad,e,fbd,e,fc
You may read this note on docs:
Separator
Specifies a string to separate each pair of adjacent elements of the array. The separator is converted to a string if necessary. If omitted, the array elements are separated with a comma (","). If separator is an empty string, all elements are joined without any characters in between them.
answered Dec 20, 2018 at 6:35
Bhojendra Rauniyar
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Comments
JavaScript is a flexible language. If it will receive something other than it is expecting, it will try to convert the passed value into a form / type that it is expecting.
As from Docs, Array's .join() method expects a string in argument to be used as a separator for joining array elements. In case you will pass it an array, JavaScript will convert this array into a string internally by calling .toString() method of Arrays. And this returned string i.e d,e,f will be used as a separator to join elements in outer array.
arr2will be converted to a string usingArray.prototype.toString()and return value (string) will be used to join elements inarr1.