I have a list m:
m = ['ABC', 'XYZ', 'LMN']
and I want output as follows:
m = [['a','x','l']
['b','y','m']
['c','z','n']]
How can this be done?
-
1Welcome to Stack Overflow! Please read How do I ask a good question? and edit your question thereafterbork– bork2019-01-11 08:40:29 +00:00Commented Jan 11, 2019 at 8:40
-
I suggest you read this SO page on how to ask a good question and then edit this accordingly: stackoverflow.com/help/how-to-askThirst for Knowledge– Thirst for Knowledge2019-01-11 08:41:16 +00:00Commented Jan 11, 2019 at 8:41
Add a comment
|
3 Answers
Use list(zip(*..)) to transpose the nested list, and use list comprehension to create nested list:
print(list(zip(*[list(i.lower()) for i in m])))
Output:
[('a', 'x', 'l'), ('b', 'y', 'm'), ('c', 'z', 'n')]
If want sub-values to be lists:
print(list(map(list,zip(*[list(i.lower()) for i in m]))))
Output:
[['a', 'x', 'l'], ['b', 'y', 'm'], ['c', 'z', 'n']]
2 Comments
kalpesh
Thanks for the help
U13-Forward
@kalpesh Don't forget to accept it if it works :-)
All you need is a list-comprehension, zip to transpose and map to convert to lower.
> m=['ABC','XYZ','LMN']
> [list(map(str.lower, sub)) for sub in zip(*m)]
[['a', 'x', 'l'], ['b', 'y', 'm'], ['c', 'z', 'n']]
3 Comments
U13-Forward
Not OP's desired output
Ma0
@U9-Forward. Oops. Did not see the transpose. Thanks!
U13-Forward
Lol, :-), happy you edited it.
m=['ABC','XYZ','LMN']
import numpy as np
new_list = [[0, 0, 0], [0, 0,0],[0,0,0]]
j = 0
for i in m:
a = list(i.lower())
print(a)
new_list[j] = a
j = j+1
np.transpose(new_list).tolist()
Output:
[['a', 'x', 'l'], ['b', 'y', 'm'], ['c', 'z', 'n']]
