Fetching href element only from the element XPath in Selenium + Python

Question

The application I am testing searches for an account based on the email ID. The email ID is unique. The result gets displayed in the form of a table with various columns. One of which is "Account Name" displaying the name of the user/account holder linked to the email address in question. In order to go into the account, one has to click on this "Account Name" value which is a link. This "Account Name" link is dynamic based on the email ID we use every time. On inspecting this link I get this:

<a href="/001m000000pFY6U?srPos=0&amp;srKp=001" data-seclke="Account" data-seclkh="60761f49cf4ed8788252c560b733bef0" data- seclki="001m000000pFY6U" data-seclkp="/001m000000pFY6U" data-seclkr="1" onmousedown="searchResultClick.mousedown(this, event)" xpath="1" style="">F John</a>

I am wondering if there is a way to retrieve/extract only the href="/001m000000pFY6U?srPos=0&srKp=001" bit from the above.

I tried the following:

elem = self.driver.find_elements_by_xpath("//a[@href]")
print(elem)

and this prints 120 lines something similar to the following: selenium.webdriver.remote.webelement.WebElement (session="502b43c903be36c997d4882f26f3c7ad",element="0.4252537892711272- 1")

Would appreciate a little help. Thanks.

Hi Dan can you share the full output of the href's as in my answer? — Moshe Slavin
– Moshe Slavin, Commented Jan 28, 2019 at 13:52

Ratmir Asanov · Accepted Answer · 2019-01-28 13:38:00Z

1

Try the following line of code:

account_links = [link.get_attribute("href") for link in driver.find_elements_by_css_selector("a[data-seclke='Account']")]

where account_links will be a list of your needed links.

Hope it helps you!

answered Jan 28, 2019 at 13:38

Ratmir Asanov

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DanSmith Over a year ago

Thank you Ratmir Asanov. It worked and returned a list and the second element at index 1, is what I need. See this: ['cs20.salesforce.com/01m000000TpFY6U/…', 'cs20.salesforce.com/001m000000pTY6U?srPos=0&srKp=001', 'mailto:[email protected]']

Moshe Slavin · Accepted Answer · 2019-01-28 12:51:54Z

0

You should use get_attribute.

For example:

elems = self.driver.find_elements_by_xpath("//a[@href]")
for i in elems:
     print(i.get_attribute("href")

Hope this helps you!

answered Jan 28, 2019 at 12:51

Moshe Slavin

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DanSmith Over a year ago

Thanks Moshe Slavin for your response. However I tried that as well but it prints 124 lines of some javascript code like: javascript:openPopupFocusEscapePounds(%27https://help.salesforce.com/apex/htdoor?loc=help&target=search_refine_a.htm&section=Search&language=en_US&release=218.6.2&instance=CS20&showSplash=true%27, %27Help%27, 1024, 768, %27width=1024,height=768,resizable=yes,toolbar=yes,status=yes,scrollbars=yes,menubar=yes,directories=no,location=yes,dependant=no%27, false, false); javascript:openPopupFocusEscapePounds(%27https://help.salesforce.com/apex/

Ali Over a year ago

Hi @DanSmith, can you share the full html anchor tag line of the above output?

DanSmith Over a year ago

<a href="/001m000000pFY6U?srPos=0&srKp=001" data-seclke="Account" data-seclkh="60761f49cf4ed8788252c560b733bef0" data-seclki="001m000000pFY6U" data-seclkp="/001m000000pFY6U" data-seclkr="1" onmousedown="searchResultClick.mousedown(this, event)">F Chau</a> Thanks @Ali

Ali Over a year ago

Try this elements = driver.find_elements_by_xpath("//a") for i in elements: print i.get_attribute('href'), I have posted the answer

Ali Over a year ago

Hi @Moshe Slavin, XPath for finding the anchor tag 'a' I have changed

|

Ali · Accepted Answer · 2019-01-28 13:33:19Z

0

Try the below code :

elements = driver.find_elements_by_xpath("//a")
for i in elements:
    print i.get_attribute('href')

'a' will identify all the anchors then by using the attribute 'href', we can get the links.

answered Jan 28, 2019 at 13:33

Ali

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DanSmith Over a year ago

No Ali CSE it does not.. Returns a lot of entries as mentioned earlier. Regards

KunduK · Accepted Answer · 2019-01-28 13:33:27Z

0

Please try this code.Check if works

  shref=driver.find_element_by_xpath('//a[@data-seclke="Account"]').get_attribute("href")
    print(shref)

answered Jan 28, 2019 at 13:33

KunduK

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DanSmith Over a year ago

Thanks Kajal. It returns one entry now which I can use to navigate to the account. However that is not what I want I want to click on the Account name link in the table (as mentioned in my original post) and then go into the account.

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