I want to do this, but it gives error :( for better understanding my problem I'm giving an example:
<?php
include 'script.php?text=hiii';
?>
content of the script.php
<?php
echo $_GET['text'];
?>
So, how can i pass an argument while including the script page?
You could set $_GET['text'] before including the file:
$_GET['text'] = 'hiii';
include 'script.php';
But this obviously won’t affect other variables like $_SERVER['REQUEST_URI'], $_SERVER['QUERY_STRING'] etc.
After you include any script, the included script will act as it's in the same page.
For yourpage.php?text=hiii, that include('script.php') will automatically print hiii, as content of script.php will be in your included page.
You could've done something like this:
<?php
$_GET['text'] = 'what you want to do';
include('script.php');
?>
Actually we don't need to add it to $_GET. just create a variable and use it. Example:
script.php
<title><?php $text; ?></title>
<!--- other code goes here -->
index.php
<?php
$text = 'Welcome back';
include 'script.php';
?>
