Getting this error org.json.JSONException: Value at 0 of type java.lang.String cannot be converted to JSONObjecton parsing

Question

I am getting this error on parsing json. Can anyone help me to solve this.

  {
"website": [
    "http://www.example.com",
    "https://buy.example.com"
],
"number": [
    "4546",
    "54256456"
],
"email": [
    "[email protected]",
    "[email protected]"
],
"address": [
    "any adddress here",
    "Address 2"
]
  }

Anyone help me to how exactly parse this json...

Json Parsing code

             String JSON_STRING = response.body().string();
                    Log.e("json_string", JSON_STRING.toString());
                    //Toast.makeText( getApplicationContext(), "Response : "+JSON_STRING, Toast.LENGTH_LONG ).show();

                    JSONObject object = new JSONObject( JSON_STRING );
                    JSONArray jsonArray = object.getJSONArray( "website" );

                        for (int i=0; i<jsonArray.length(); i++)
                        {
                            JSONObject website = jsonArray.getJSONObject( i );
                            Log.e("website", website.toString());
                        }

Please post JSON parsing code.

Sanju Rajpal
– Sanju Rajpal

2019-04-05 05:38:32 +00:00
Commented Apr 5, 2019 at 5:38 — Sanju Rajpal
– Sanju Rajpal, Commented Apr 5, 2019 at 5:38

Sanju Rajpal · Accepted Answer · 2019-04-05 05:55:24Z

1

try this code

 try {
        JSONObject jsonObject = new JSONObject(json);
        JSONArray websites = jsonObject.getJSONArray("website");
        for (int i = 0; i < websites.length(); i++) {
            Log.d("TAG", websites.getString(i));
        }

    } catch (Exception e) {
        e.printStackTrace();
    }

answered Apr 5, 2019 at 5:55

Sanju Rajpal

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1 Comment

Learner_coding Over a year ago

Yes, i got the answer and i commented below.. Your answer is also correct i used the same approach...

FranzHuber23 · Accepted Answer · 2019-04-05 05:52:13Z

1

// for email array and response variable is your jsonObject coming from server
JSONArray jsonArray = response.getJSONArray("email")
for(int i = 0; i < jsonArray.length(); i++){
   //get email one by one 
   String email = jsonArray.getString(i)
}

Let me know if it is working.

edited Apr 5, 2019 at 5:52

FranzHuber23

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answered Apr 5, 2019 at 5:19

Rohit Singh

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2 Comments

Learner_coding Over a year ago

JSONObject object = new JSONObject( response.body().string() ); JSONArray jsonArray = object.getJSONArray("email"); for(int i = 0 ;i < jsonArray.length();i++){ String email = jsonArray.getString(i); Log.e("emailjson", email.toString()); }

Rohit Singh Over a year ago

ok i thought you are getting response from server in jsonObject not in string otherwise we have to convert string to jsonObject.

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