YAML parse return object not Array using PHP

Question

I want to use a YAML configuration file, for that, I download symfony/yaml package using composer.

I create my test YAML file content:

testing:
  test: 2

and to parse it I use this code :

$yaml = Yaml::parse(file_get_contents('test.yml'));
var_dump($yaml->testng);

But, I get this error 'Trying to get property 'testng' of non-object' because the parse return array and I want to get an object.

I tried to add (object) but it works just for the first attribute.

Is there any solution?

This may help, but it looks like the yaml needs to be in Yaml::DUMP_OBJECT format symfony.com/doc/current/components/… — Arleigh Hix
– Arleigh Hix, Commented Apr 16, 2019 at 4:53
There seems to be something very wrong if your error message indicates testng causes an error when that string is not even in your input YAML. — Anthon
– Anthon, Commented Apr 16, 2019 at 5:35

Styx · Accepted Answer · 2019-04-16 05:44:39Z

6

According to documentation you should just pass Yaml::PARSE_OBJECT_FOR_MAP as a second parameter of Yaml::parse():

$yaml = Yaml::parse(file_get_contents('test.yml'), Yaml::PARSE_OBJECT_FOR_MAP);

answered Apr 16, 2019 at 5:44

Styx

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1 Comment

sayou Over a year ago

Thanks for your reply sir

Black Flag · Accepted Answer · 2019-04-15 22:10:56Z

0

you can use this function

  public function toObject($array) {
        $obj = new stdClass();
        foreach ($array as $key => $val) {
            $obj->$key = is_array($val) ? $this->toObject($val) : $val;
        }
        return $obj;
    }

answered Apr 15, 2019 at 22:10

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