Sorting an array of objects with lodash: not working

Question

I have an array that looks like this one (it has more objects, but the structure is the same):

[
  {
      especiality: "surgery",
      users: [
          {
              id: "182",
              country: "Colombia",
              province: "Bogota",
              telephone: "211112212",
              neighbourhood: "La Santa"
              region: "South",
          },
          {
            id: "182",
            country: "Venezuela",
            province: "Caracas",
            telephone: "322323333",
            region: "North",
        },
        {
          id: "183",
          country: "Brasil",
          telephone: "23232333",
          neighbourhood: "Santos"
          region: "South",
      },
      ]
  },

I want the addresses, if the ID is the same, to compose one single array (I need to map these elements). The outlook should look like this one:

user: [{id: 182, locations[(if they exist)               
              country: "Colombia",
              province: "Bogota",
              telephone: "211112212",
              neighbourhood: "La Santa"
              region: "South"], [country: "Venezuela",
            province: "Caracas",
            telephone: "322323333",
            region: "North"],}]

I´m currently trying this, but it´s not working at all:

getGroups = test => {
  _.chain(test)
  .groupBy("id")
  .toPairs()
  .map(item => _.zipObject(["id", "country", "province", "neighbourhood", "region"], item))
  .value();
  return test
  }

What am I doing wrong and how can I account for values that may not be available in all objects?

why do you have an outer array? are there more items with users? do you want to rouo all others as well? — Nina Scholz
– Nina Scholz, Commented Apr 17, 2019 at 12:52
The outer array is the way the data structure I´m dealing with is structured. Yes, there are more items with users, but they all share the same structure — user11331566
– user11331566, Commented Apr 17, 2019 at 12:58

Ori Drori · Accepted Answer · 2019-04-17 13:09:10Z

After grouping the items by the id, map the groups, and create an object with the id, and the items of the group as locations. Map the locations, and use _.omit() to remove the id from them.

I'm not sure about how you want to handle the outer array. I've used _.flatMap() to get a single array of users, but there's a commented option if you need to maintain the original structure.

getGroups = test =>
  _(test)
  .groupBy("id")
  .map((locations, id) => ({
    id,
    locations: _.map(locations, l => _.omit(l, 'id'))
  }))
  .value();

const data = [{"especiality":"surgery","users":[{"id":"182","country":"Colombia","province":"Bogota","telephone":"211112212","neighbourhood":"La Santa","region":"South"},{"id":"182","country":"Venezuela","province":"Caracas","telephone":"322323333","region":"North"},{"id":"183","country":"Brasil","telephone":"23232333","neighbourhood":"Santos","region":"South"}]}];

const result = _.flatMap(data, ({ users }) => getGroups(users));

/** maintains the original structure
const result = _.map(data, ({ users, ...rest }) => ({
  ...rest,
  users: getGroups(users)
}));
**/

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.js"></script>

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