bash script to create and print string into files from list

Question

I'm on opensus 11.3 and I am looking for a bash script to do the following:

Create directories and rename them from a .txt list, each new name is a new line on that .txt
Copy file.php from to each new directory, and rename all file.php files in those directories to a specific name.
Print a "/< php ? >/" string into the first line in each of those files.

I assume the best and fastest to accomplish this will be in bash, if you have another idea I will be happy to listen.

See my answer. You didn't say to what name the dirs should be renamed & to what name should be file.php renamed. Provide this information and I will update my answer accordingly — pajton
– pajton, Commented Apr 8, 2011 at 14:50
The folder names should taken by order from list.txt and the file indide is a specific name "filename.php". I tried What you wrote it does not create the folders. — Jack_R
– Jack_R, Commented Apr 8, 2011 at 15:01
Great it does that, Thanks pajton, you saved me long time here. :) — Jack_R
– Jack_R, Commented Apr 8, 2011 at 15:09
let me ask you, what if the string that it prints inside will be the a php code that will like <php $city= "the folder name from the list" ?> ? Is there a way to do that ? — Jack_R
– Jack_R, Commented Apr 8, 2011 at 15:14

pajton · Accepted Answer · 2011-04-08 16:19:57Z

4

Edit:: This is the version modified according to OP's last comment:

#/bin/bash

while read name; do
    # prepare file to copy into new dirs
    echo "\<php \$city= \"$name\" ?\>" > tempfile
    cat file.php >> tempfile

    # create dir & copy modified file.php into it
    mkdir -p "$name"
    cp tempfile "$name"/filename.php
done < names.txt

edited Apr 8, 2011 at 16:19

answered Apr 8, 2011 at 14:49

pajton

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1 Comment

Adam Matan Over a year ago

use mkdir -p, to avoid errors when crating subdirectories directly.

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