Say I get this line of JSON
[{u'status': u'active', u'due_date': None, u'group': u'later', u'task_id': 73286}]
How can I convert those separate values to strings? So I can say
Print Status
And it returns
active
-
docs.python.org/tutorial/datastructures.htmlIgnacio Vazquez-Abrams– Ignacio Vazquez-Abrams2011-04-10 21:26:41 +00:00Commented Apr 10, 2011 at 21:26
Add a comment
|
3 Answers
That is NOT a "line of JSON" as received from an external source. It looks like the result of json.loads(external_JSON_string). Also Print Status won't work; you mean print status.
>>> result = [{u'status': u'active', u'due_date': None, u'group': u'later', u'task_id': 73286}]
>>> print result[0]['status']
active
This is what a "line of JSON" looks like:
>>> import json
>>> json.dumps(result)
'[{"status": "active", "due_date": null, "group": "later", "task_id": 73286}]'
>>>
EDIT: If using Python 2.5, use import simplejson as json instead of import json. Make your code a bit more future-proof by doing this:
try:
import json
except ImportError:
import simplejson as json
1 Comment
Praxiteles
So if what he is showing isn't a line of JSON - then what does one use to stringify that? Is that already a string? Is there something that needs to be done to it to treat it as a string (i.e. "un-unicode" it for example)?
First of all, that ain't JSON as was already pointed out - it's python already.
I think you want the keys of the dict automatically transform into local variables. This would be a really bad idea, although in theory, it's possible using locals ():
result = [{u'status': u'active', u'due_date': None, u'group': u'later', u'task_id': 73286}]
for k, v in result[0].items():
locals() [k] = v
print status # prints active
Some problems:
- Your keys might overwrite some existing local variables
- Keys might be unicode, how would you access the variable names?
Also, as stated in the python docs, locals () should not be modified.
In short: do it like this:
print result[0]['status']
Comments
import simplejson
_dict = simplejson.loads(json_data)
for entry in _dict:
# loop over list
print entry.get('status','Failure')
# Find key in dict/entry
1 Comment
HankSmackHood
I get this error: File "/Library/Python/2.5/site-packages/simplejson/__init__.py", line 385, in loads return _default_decoder.decode(s) File "/Library/Python/2.5/site-packages/simplejson/decoder.py", line 402, in decode obj, end = self.raw_decode(s, idx=_w(s, 0).end()) TypeError: expected string or buffer