So i have a string x = "10101" and i need to put into any string y the hex value of the binary in x. So if x="10101" then y="0x15"
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Is there a problem with our answers?Rob– Rob2011-05-03 04:20:21 +00:00Commented May 3, 2011 at 4:20
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3 Answers
The simplest way to do this is using a [bitset][1]:
#include <iostream>
#include <string>
#include <bitset>
using namespace std;
int main(){
string binary_str("11001111");
bitset<8> set(binary_str);
cout << hex << set.to_ulong() << endl;
}
But I read that it's not the most efficient way... Depends on what you whant. Remember that premature optimisation is the root of all evil.
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You should probably use strtol ( http://en.wikipedia.org/wiki/Strtol ) function with the base 2 to convert x to the integer and then use sprintf to format the result string.
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I don't want to provide you with the complete answer.
That said, the basic idea should be fill the start of the string with up to 3 zero's so that you can split the string into substrings with a length of 4. This can then easily be turned into hex by a variety of ways, the easiest being just using a switch case statement. There would only be 16 cases'
