Javascript Object to array then remove element

Question

I have this object

Object {
  "87291": "valid",
  "1873681927": "valid",
  "nwq89j8jw0qj9": "valid",
  "oVFYfWIUOsONE6JyMGYAbnsPMAr1": "valid",
}

what i want to do is remove object based on key value and return as array.

i used this code :

    let attay = {
      "87291": "valid",
      "1873681927": "valid",
      "nwq89j8jw0qj9": "valid",
      "oVFYfWIUOsONE6JyMGYAbnsPMAr1": "valid",
    }


    let aar = Object.entries(attay)
    attay = Object.keys(attay)

    for(var i = 0; i < attay.length; i++) {
      if(attay[i] == 'oVFYfWIUOsONE6JyMGYAbnsPMAr1'){
        console.log("found "+attay[i]+" at "+i)
        aar.splice(i, 1);
        console.log(aar)
      }else{
        console.log("NOT found at "+i)        
      }
    }

this code worked okay but the output after remove element is like this

Array [
  Array [
    "87291",
    "valid",
  ],
  Array [
    "1873681927",
    "valid",
  ],
  Array [
    "nwq89j8jw0qj9",
    "valid",
  ],
]

expected output should be like

Array [
      "87291": "valid",
      "1873681927": "valid",
      "nwq89j8jw0qj9": "valid",
    ]

If you pretend to have key/value pairs in your expected output, then do not expect to use an array for it. — Shidersz
– Shidersz, Commented Jun 5, 2019 at 21:21
The "expected output" does not make sense; that's not valid syntax. — Pointy
– Pointy, Commented Jun 5, 2019 at 21:21
Also just delete attay.oVFYfWIUOsONE6JyMGYAbnsPMAr1' and then do whatever you want to the original object. — Pointy
– Pointy, Commented Jun 5, 2019 at 21:22
i thought about this but tbh i didn't try it cuz u'm using React Native. — Sandy Smarue
– Sandy Smarue, Commented Jun 5, 2019 at 21:31

TheWandererLee · Accepted Answer · 2019-06-05 21:40:25Z

4

Maybe I'm misunderstanding but it seems like you're over-complicating this. You want to remove the property from the object?

let arr = {
  "87291": "valid",
  "1873681927": "valid",
  "nwq89j8jw0qj9": "valid",
  "oVFYfWIUOsONE6JyMGYAbnsPMAr1": "valid",
}

let removeKey = "oVFYfWIUOsONE6JyMGYAbnsPMAr1"
delete arr[removeKey]; // Remove the property

console.log(arr);

answered Jun 5, 2019 at 21:40

TheWandererLee

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Comments

danh · Accepted Answer · 2019-06-05 21:28:49Z

1

If your runtime is okay with the relatively modern entries (and fromEntries), then you can get what you want simply. (Guessing that you're really aiming for an object output, not an array based on the syntax in your question).

let attay = {
  "87291": "valid",
  "1873681927": "valid",
  "nwq89j8jw0qj9": "valid",
  "oVFYfWIUOsONE6JyMGYAbnsPMAr1": "valid",
}

let removeKey = "oVFYfWIUOsONE6JyMGYAbnsPMAr1"

let pairs = Object.entries(attay).filter(e => e[0] != removeKey)
const obj = Object.fromEntries(pairs);
console.log(obj)

answered Jun 5, 2019 at 21:28

danh

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Comments

Sandy Smarue · Accepted Answer · 2019-06-05 21:37:35Z

1

the answer came from @Pointy

delete attay.oVFYfWIUOsONE6JyMGYAbnsPMAr1

simple and worked like charm and also worked on React Native

answered Jun 5, 2019 at 21:37

Sandy Smarue

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Comments

Jack Bashford · Accepted Answer · 2019-06-05 21:31:57Z

0

You can avoid the less supported fromEntries by using a simple reduce.

let attay = {
  "87291": "valid",
  "1873681927": "valid",
  "nwq89j8jw0qj9": "valid",
  "oVFYfWIUOsONE6JyMGYAbnsPMAr1": "valid",
};
const remove = "oVFYfWIUOsONE6JyMGYAbnsPMAr1";
const res = Object.entries(attay).reduce((acc, [k, v]) => k == remove ? acc : (acc[k] = v, acc), {});
console.log(res);

answered Jun 5, 2019 at 21:31

Jack Bashford

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Comments

Aziz.G · Accepted Answer · 2019-06-06 12:07:20Z

0

you could use delete this way if the key match with the propriety:

const obj = {
  "87291": "valid",
  "1873681927": "valid",
  "nwq89j8jw0qj9": "valid",
  "oVFYfWIUOsONE6JyMGYAbnsPMAr1": "valid",
}

const key = "87291";

delete obj[key]



console.log(obj)

edited Jun 6, 2019 at 12:07

answered Jun 5, 2019 at 21:27

Aziz.G

3,7813 gold badges20 silver badges38 bronze badges

3 Comments

Jack Bashford Over a year ago

Why are you using map for a simple iteration?

Jack Bashford Over a year ago

You could just use forEach().

TheWandererLee Over a year ago

delete obj[key] already searches through the object to find the key specified, there is no need to write your own iterator.

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