Angular Sort Array Object by value inside object

Question

How get the object by filtering key value inside the object? I have objects below where I need to only pull data which has session_id:23

data = [{ name: "fist Name", session_id : "23", login: "date" }, { name: "Second Name", session_id : "18", login: "date" }, { name: "Third Name", session_id : "23", login: "date" }];

I tried Angular Filter and Map method to filter this out but dosent seem to work for me here.
.pipe(
    map((res) => {
        res => res.filter(res => res.season_id == 23)
        console.log(res);
    })
)

ngOnInit() {
    this._service.getData();
    this._service.updatedPlayer
        .pipe(
            map((res) => {
                res => ress.filter(res => res.season_id == 23)
                console.log(res);
            })
        )
        .subscribe(
            (playerSession) => {
                this.playerSessionUpdate = playerSession;
            }
        )

}

Fredrik_Borgstrom · Accepted Answer · 2019-06-10 08:17:57Z

2

I think you're confusing arrays with streams.

You need to use the filter method of Array, not the filter operator of observables. So if this._service.updatedPlayer contains your observable stream of data, do this:

this._service.updatedPlayer.subscribe(data => {
  this.playerSessionUpdate = data.filter(res => res.season_id == 23);
}

this.playerSessionUpdate will now contain your filtered data.

answered Jun 10, 2019 at 8:17

Fredrik_Borgstrom

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1 Comment

Vicky Parab Over a year ago

that was my mistake, good point to be noted here array and stream/observables. Thanx for your help Fredrik

Francisco Santorelli · Accepted Answer · 2019-06-10 07:41:41Z

0

your pipe method map must return something. So you should actually do

 map((res) => {
          return res.filter(res => res.season_id === 23)
     })

answered Jun 10, 2019 at 7:41

Francisco Santorelli

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3 Comments

Vicky Parab Over a year ago

this dosent work for me either, this output straing the function like this: function (ress) { return ress.filter(function (ress) { return ress.season_id == 23; }); }

Francisco Santorelli Over a year ago

but I don't understand where does the 'ress' variables comes from. You have a 'res' and a 'ress' in your example. Is it a typo? please clarify so i can try to help more :D

Vicky Parab Over a year ago

Its res only sir, can we filter this it cannot seem to be filtered with this code.

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