242

Possible Duplicate:
What is the most efficient way to clone a JavaScript object?

I need to copy an (ordered, not associative) array of objects. I'm using jQuery. I initially tried

jquery.extend({}, myArray)

but, naturally, this gives me back an object, where I need an array (really love jquery.extend, by the way).

So, what's the best way to copy an array?

1
  • If you don't want an object in return then specify [] instead of {} Commented Nov 7, 2017 at 8:33

8 Answers 8

292

Since Array.slice() does not do deep copying, it is not suitable for multidimensional arrays:

var a =[[1], [2], [3]];
var b = a.slice();

b.shift().shift();
// a is now [[], [2], [3]]

Note that although I've used shift().shift() above, the point is just that b[0][0] contains a pointer to a[0][0] rather than a value.

Likewise delete(b[0][0]) also causes a[0][0] to be deleted and b[0][0]=99 also changes the value of a[0][0] to 99.

jQuery's extend method does perform a deep copy when a true value is passed as the initial argument:

var a =[[1], [2], [3]];
var b = $.extend(true, [], a);

b.shift().shift();
// a is still [[1], [2], [3]]
Sign up to request clarification or add additional context in comments.

5 Comments

Thanks Noah. Looks like my biggest problem was that I was giving $.extend and object as its first argument, not an array.
Can you explain what is the purpose of b.shift().shift() here?
b is just being manipulated to show that a and b don't hold the same value. Shouldn't a and b be represented as [[3]]? Shift removes the first value in an array entirely whether it is of any type. It doesn't perform a recursive search for a primitive type and then remove that. The length of an array that holds the context for the method always decreases by 1 and is edited in place.
Thank you! Your line: var b = $.extend(true, [], a); saved my life! I used $.extend(true, {}, a) braces instead of square brackets!
thanks it helped very much , normally when we copy array by direct assignment way , when one array is changed then other copied array also get changes , so this method do real copy.
32

$.extend(true, [], [['a', ['c']], 'b'])

That should do it for you.

1 Comment

This will not work for multi dimensional arrays, you have to use "true" as first argument as mentioned in answer by @Noah Sussman
21

I realize you're looking for a "deep" copy of an array, but if you just have a single level array you can use this:

Copying a native JS Array is easy. Use the Array.slice() method which creates a copy of part/all of the array.

var foo = ['a','b','c','d','e'];
var bar = foo.slice();

now foo and bar are 5 member arrays of 'a','b','c','d','e'

of course bar is a copy, not a reference... so if you did this next...

bar.push('f');
alert('foo:' + foo.join(', '));
alert('bar:' + bar.join(', '));

you would now get:

foo:a, b, c, d, e
bar:a, b, c, d, e, f

4 Comments

Note that this is not a deep copy.
similar: var a = [1,2,3]; var b = ([]).concat(a); b is a copy
Array.slice does not provide a deep copy, which is pretty specifically the question being asked here.
The author has put deep in parenthesis, so any answer regarding copying is welcome. The text of the actual question doesn't even contain the word deep at all.
13

Everything in JavaScript is pass by reference, so if you want a true deep copy of the objects in the array, the best method I can think of is to serialize the entire array to JSON and then de-serialize it back.

1 Comment

Primitives are not passed by reference. Objects (incl. arrays) are, though.
7

If you want to use pure JavaScript then try this:

 var arr=["apple","ball","cat","dog"];
 var narr=[];

 for(var i=0;i<arr.length;i++){
     narr.push(arr[i]);
 }
 alert(narr); //output: apple,ball,vat,dog
 narr.push("elephant");
 alert(arr); // output: apple,ball,vat,dog
 alert(narr); // apple,ball,vat,dog,elephant

Comments

3

how about complex types? when array contains objects... or any else

My variant:

Object.prototype.copy = function(){
    var v_newObj = {};
    for(v_i in this)
        v_newObj[v_i] = (typeof this[v_i]).contains(/^(array|object)$/) ? this[v_i].copy() : this[v_i];
    return v_newObj;
}

Array.prototype.copy = function(){
    var v_newArr = [];
    this.each(function(v_i){
        v_newArr.push((typeof v_i).contains(/^(array|object)$/) ? v_i.copy() : v_i);
    });
    return v_newArr;
}

It's not final version, just an idea.

PS: method each and contains are prototypes also.

Comments

2

I've come across this "deep object copy" function that I've found handy for duplicating objects by value. It doesn't use jQuery, but it certainly is deep.

http://www.overset.com/2007/07/11/javascript-recursive-object-copy-deep-object-copy-pass-by-value/

1 Comment

Thanks, was looking for a catch-all clone (sometimes have an object, sometimes an array of objects).
2

I plan on releasing this code in the next version of jPaq, but until then, you can use this if your goal is to do a deep copy of arrays:

Array.prototype.clone = function(doDeepCopy) {
    if(doDeepCopy) {
        var encountered = [{
            a : this,
            b : []
        }];

        var item,
            levels = [{a:this, b:encountered[0].b, i:0}],
            level = 0,
            i = 0,
            len = this.length;

        while(i < len) {
            item = levels[level].a[i];
            if(Object.prototype.toString.call(item) === "[object Array]") {
                for(var j = encountered.length - 1; j >= 0; j--) {
                    if(encountered[j].a === item) {
                        levels[level].b.push(encountered[j].b);
                        break;
                    }
                }
                if(j < 0) {
                    encountered.push(j = {
                        a : item,
                        b : []
                    });
                    levels[level].b.push(j.b);
                    levels[level].i = i + 1;
                    levels[++level] = {a:item, b:j.b, i:0};
                    i = -1;
                    len = item.length;
                }
            }
            else {
                levels[level].b.push(item);
            }

            if(++i == len && level > 0) {
                levels.pop();
                i = levels[--level].i;
                len = levels[level].a.length;
            }
        }

        return encountered[0].b;
    }
    else {
        return this.slice(0);
    }
};

The following is an example of how to call this function to do a deep copy of a recursive array:

// Create a recursive array to prove that the cloning function can handle it.
var arrOriginal = [1,2,3];
arrOriginal.push(arrOriginal);

// Make a shallow copy of the recursive array.
var arrShallowCopy = arrOriginal.clone();

// Prove that the shallow copy isn't the same as a deep copy by showing that
// arrShallowCopy contains arrOriginal.
alert("It is " + (arrShallowCopy[3] === arrOriginal)
    + " that arrShallowCopy contains arrOriginal.");

// Make a deep copy of the recursive array.
var arrDeepCopy = arrOriginal.clone(true);

// Prove that the deep copy really works by showing that the original array is
// not the fourth item in arrDeepCopy but that this new array is.
alert("It is "
    + (arrDeepCopy[3] !== arrOriginal && arrDeepCopy === arrDeepCopy[3])
    + " that arrDeepCopy contains itself and not arrOriginal.");

You can play around with this code here at JS Bin.

1 Comment

Interesting. @Chris West can you say what issues that your answer addressees that jQuery extend does not? Many thanks.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.