join array with a condition - Javascript

Question

I have a matrix with "seccion" keys and I want to join it by "seccion". Help me here I leave an example. I am already grateful for your support. Sorry for my English

At the beginning I have this then try to join them:

{0: {seccion: "0", stitulo: "titulo_test1"}, 
 1: {seccion: "0", ssub: "sub_test1"},
 2: {seccion: "1", stitulo: "titulo_test2"},
 3: {seccion: "1", ssub: "sub_test2"}
}

What I do is go through all the objects with an assigned class, but the "i" counter overwrites them:

var secciones={};
$('#formSecciones').find('.secc').each(function(i,s) {
    secciones[`$(s).closest('.dd-item').attr('data-id')] = {};
    secciones[`$(s).closest('.dd-item').attr('data-id')][i] = {};
    secciones[`$(s).closest('.dd-item').attr('data-id')][i][s.name] = s.value;
});

Result:

{0:{1:{ssub: "sub_test1"}},
 1:{3:{ssub: "sub_test2"}}
}

This is what I want to get:

{0: {ssub: "sub_test1", stitulo: "titulo_test1"},
 1: {stitulo: "titulo_test2", ssub: "sub_test2"}
}

Your code isn't operating on the object, it's operating on DOM elements. — Barmar
– Barmar, Commented Jun 18, 2019 at 17:22

Barmar · Accepted Answer · 2019-06-18 17:28:12Z

1

You should only create a new object if the object doesn't already exist at that key.

Also, you don't want nested arrays, so you don't need [i] in the target of the assignment.

var secciones={};
$('#formSecciones').find('.secc').each(function(i,s) {
    var id = $(s).closest('.dd-item').attr('data-id');
    if (!secciones[id]) {
        secciones[id] = {};
    }
    secciones[id][s.name] = s.value;
});

answered Jun 18, 2019 at 17:28

Barmar

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1 Comment

ErixHM Over a year ago

thank you very much I am very grateful, I had already tried something similar but I do not remember what was wrong.

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