Extract numeric values from a string for python

Question

I have a string with contains numeric values which are inside quotes. I need to remove numeric values from these and also the [ and ]

sample string: texts = ['13007807', '13007779']

texts = ['13007807', '13007779'] 
texts.replace("'", "")
texts..strip("'")

print texts 

# this will return ['13007807', '13007779']

So what i need to extract from string is:

13007807
13007779

Umm... does numbers = [int(s) for s in texts] do what you're after (given your sample)? Or is texts actually a string itself? — Jon Clements
– Jon Clements, Commented Jul 17, 2019 at 13:47
texts was a list i converted to a string texts = str(re.findall(r"\d+", texts)) — Seán Dempsey
– Seán Dempsey, Commented Jul 17, 2019 at 13:53

Youcef4k · Accepted Answer · 2019-07-17 13:58:47Z

1

If your texts variable is a string as I understood from your reply, then you can use Regular expressions:

import re
text = "['13007807', '13007779']"
regex=r"\['(\d+)', '(\d+)'\]"
values=re.search(regex, text)
if values:
    value1=int(values.group(1))
    value2=int(values.group(2))

output:

value1=13007807

value2=13007779

answered Jul 17, 2019 at 13:58

Youcef4k

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Comments

ncica · Accepted Answer · 2019-07-17 13:59:50Z

1

You can use * unpack operator:

texts = ['13007807', '13007779']
print (*texts)

output:

13007807 13007779

if you have :

data = "['13007807', '13007779']"
print (*eval(data))

output:

13007807 13007779

edited Jul 17, 2019 at 13:59

answered Jul 17, 2019 at 13:51

ncica

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Comments

mad_ · Accepted Answer · 2019-07-17 14:04:52Z

0

The easiest way is to use map and wrap around in list

list(map(int,texts))

Output

[13007807, 13007779]

If your input data is of format data = "['13007807', '13007779']" then

import re
data = "['13007807', '13007779']"
list(map(int, re.findall('(\d+)',data)))

or

list(map(int, eval(data)))

edited Jul 17, 2019 at 14:04

answered Jul 17, 2019 at 13:56

mad_

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