PHP foreach inside variable

Question

How would I include a foreach function inside a variable. The code should explain what I mean.

$list = get_posts('post_type=services&numberposts=-1');
    foreach ($list as $post) :
        $title = $post->post_title; 


    $return = '<li>
                    <a href="#main_content_inner" onClick="slide(this); return false" rel="catalogue_sevices_page">'.$title.'</a>
                </li>';
                endforeach;

That is not quite correct. I am trying to make it so that $return displays all the posts from the type services in the format

So effectively I am after::

$list = get_posts('post_type=services&numberposts=-1');
    foreach ($list as $post) :
        $title = $post->post_title;

And therefore the output from $return should look something like this

<li><a href="#content1" onClick="slide(this); return false" rel="catalogue_sevices_page">Title 1</a></li>
<li><a href="#content2" onClick="slide(this); return false" rel="catalogue_sevices_page">Title 2</a></li>
<li><a href="#content3" onClick="slide(this); return false" rel="catalogue_sevices_page">Title 3</a></li>

Any ideas,

Shakti Singh · Accepted Answer · 2011-04-19 16:23:16Z

4

you have to use concatenation to store data in a variable with in foreach loop

 $return .= '<li>....

and then return the $return variable before foreach end

 return $return;
endforeach;

answered Apr 19, 2011 at 16:23

Shakti Singh

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Frank Farmer · Accepted Answer · 2011-04-19 16:23:50Z

3

Simply append with the .= operator.

$return = '';
$list = get_posts('post_type=services&numberposts=-1');
foreach ($list as $post) {
    $title = $post->post_title; 
    $return .= '<li>
                <a href="#main_content_inner" onClick="slide(this); return false" rel="catalogue_sevices_page">'.$title.'</a>
            </li>';
}
return $return;

answered Apr 19, 2011 at 16:23

Frank Farmer

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