How can I implement the PHP output to a array with keys numbers

Question

The output of the script is: "Outstanding 1... Outstanding 2... Outstanding 3..."

How can I output the for example only the second position of the array, so that I can output the results separately?

Like this: $out[1]

<?php
$html = '
    <div class="page-wrapper">
        <section class="page single-review" itemtype="http://schema.org/Review" itemscope="" itemprop="review">
            <article class="review clearfix">
                <div class="review-content">
                    <div class="review-text" itemprop="reviewBody">
                    Outstanding 1... 
                    </div>
                    <div class="review-text" itemprop="reviewBody">
                    Outstanding 2... 
                    </div>
                </div>
            </article>
        </section>
    </div>
    <div class="review-text" itemprop="reviewBody">
    Outstanding 3... 
    </div>
';

$dom = new DOMDocument;
$dom->loadHTML ($html);
$xpath = new DOMXPath ($dom);
foreach ($xpath->query (".//div[@class='review-text']") as $review)
{
    $out = $review->nodeValue;
    echo $out;
}

?>

What keeps you from taking the second element of that array and perform whatever you like? — Nico Haase
– Nico Haase, Commented Aug 1, 2019 at 14:53

Martin Dimitrov · Accepted Answer · 2019-08-02 19:41:11Z

1

There are two ways to do this. Either add the entire query result to an array like this

$arr = $xpath->query (".//div[@class='review-text']")

and then call it by

$arr[1]->nodeValue

or if the HTML is big, you can really save memory by doing

    $counter = 0;
    foreach ($xpath->query (".//div[@class='review-text']") as $review)
    {
        if ($counter == 1) {
            $out = $review->nodeValue;
            echo $out;
        }
        $counter++;
    }

Depending on what you need, you can pick one of the options. Also if you need to run other code, but the printing in the foreach, the second way can do that too.

edited Aug 2, 2019 at 19:41

answered Aug 1, 2019 at 11:49

Martin Dimitrov

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7 Comments

Sinalco Over a year ago

This is not what I want. I will not Display the $out values in different Lines. I will bring the values to an array with key numbers. So that I can output only Outstanding 2.... or only Outstanding 3...

Martin Dimitrov Over a year ago

@Sinalco Sorry, I misunderstood your question. I've edited with changes.

Martin Dimitrov Over a year ago

@Sinalco Please accept the answer then, so it can help other people with similar issue.

Sinalco Over a year ago

Sorry Martin, but the last answer from Will is the best answer to help other People.

Martin Dimitrov Over a year ago

@Sinalco I don't see how it is better for the general use. He is easier for exactly your case, as you can just copy paste his entire answer, while I give different options that are not 100% for your answer only, while giving explanation, but after all, it is indeed your choice.

|

Will · Accepted Answer · 2019-08-01 14:52:24Z

0

You shoul try something like this

<?php
$html = '
<div class="page-wrapper">
    <section class="page single-review" itemtype="http://schema.org/Review" itemscope="" itemprop="review">
        <article class="review clearfix">
            <div class="review-content">
                <div class="review-text" itemprop="reviewBody">
                    Outstanding 1...
                </div>
                <div class="review-text" itemprop="reviewBody">
                    Outstanding 2...
                </div>
            </div>
        </article>
    </section>
</div>
<div class="review-text" itemprop="reviewBody">
    Outstanding 3...
</div>
';

$dom = new DOMDocument;
$dom->loadHTML ($html);
$xpath = new DOMXPath ($dom);
$reviews = $xpath->query (".//div[@class='review-text']");

echo $reviews[1]->nodeValue; // Outstanding 2...

The point is to store all the reviews in an array and then echo the one you want from the array.

edited Aug 1, 2019 at 14:52

answered Aug 1, 2019 at 11:50

Will

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1 Comment

Will Over a year ago

Ooops, I mispelled a variable. Of courses you first added your own $html, yes ? I edit so you have the full example.

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