How to set php variable as value of input text html

Question

I have a below code which has a input text box and its value I want to set is php variable. Below is the code:

index.php

<!DOCTYPE html>
<html>

    <head>
        <title>My Website</title>
        <link href="main.css" rel="stylesheet" type="text/css" href="" />
    </head>

    <body>
        <form enctype="multipart/form-data" action="upload.php" method="POST">
            <input type="hidden" name="MAX_FILE_SIZE" value="512000" />
            Select file: <input name="userfile" type="file"/>

            <input type="text" name="filename" value=<?php echo $filename; ?> />

            <input type="submit" value="Send File" multiple/>
        </form>
    </body>

</html>

Now the above code is working fine and it does what is written in upload.php. But for some reason, inside the input type text box, there is <br in it. I am not able to make it clear. Also it says undefined variable filename. Below is the screenshot of the webpage:

Can anyone please help in why it says filename undefined variable and why <br is shown on input type text box. I have tried below approach but nothing worked:

<input type="text" name="filename" value="<?php echo $filename; ?>" />

<input type="text" name="filename" value='<?php echo $filename; ?>' />

$filename isn't defined in script. Initialize it prior to using it. — dazed-and-confused
– dazed-and-confused, Commented Aug 10, 2019 at 5:00

Dilip Hirapara · Accepted Answer · 2019-08-10 05:15:47Z

1

It just becuase of you are not getting $filename from php.

<?php $file = isset($filename) ? $filename : ''; ?> //if value doesn't exist it'll take '' value.
<input type="text" name="filename" value="<?php echo $file; ?>" />

edited Aug 10, 2019 at 5:15

answered Aug 10, 2019 at 5:07

Dilip Hirapara

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1 Comment

S Andrew Over a year ago

No, its not working. I have attached a screenshot of its response.

Marek Hulka · Accepted Answer · 2019-08-10 05:16:00Z

1

You need to correctly set up variable value first. What you have done is not assignation, it is not in PHP tags. This is correct:

<?php $file = isset($filename) ? $filename : ''; ?>
<input type="text" name="filename" value="<?php echo $file; ?>" />

answered Aug 10, 2019 at 5:16

Marek Hulka

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