PHP Access objects and store it in an array or access objects as arrays? [duplicate]

Question

I'm currently working on a project where I have to access the objects from Audience Segments and export the data that comes together with it in an excel format.

I'm still new to PHP and I can't seem to figure my way around this. Here's a sample code

if ($page->getResults() !== null) {
    $totalResultSetSize = $page->getTotalResultSetSize();
    $i = $page->getStartIndex();


    $myfile = fopen($fileName.".xls", "a") or die("Unable to open file!");

    foreach ($page->getResults() as $audienceSegment) {

        $id =  $audienceSegment->getId(); //long
        $name =  $audienceSegment->getName(); //string
        $size = $audienceSegment->getSize(); //long

        fputcsv($myfile,"$id, $name, $size");
        $i++;

    }
    fclose($myfile);
}

As you can see in the code, I'm trying to export the data from the variables $id, $name, and $size. Since I'm using fputcsv, I'm getting this error,

**Warning: fputcsv() expects parameter 2 to be array**

Hence, that's the reason why I want the objects to come in an array. Can someone help me?

fputcsv - 'fields - An array of strings.' - Example

Script47
– Script47

2019-09-18 09:48:29 +00:00
Commented Sep 18, 2019 at 9:48 — Script47
– Script47, Commented Sep 18, 2019 at 9:48

Death-is-the-real-truth · Accepted Answer · 2019-09-19 05:51:52Z

1

Have you tried to use an array instead? You are passing a second argument as a string. Instead of:

fputcsv($myfile,"$id, $name, $size");

try:

fputcsv($myfile,[$id, $name, $size]);

edited Sep 19, 2019 at 5:51

Death-is-the-real-truth

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answered Sep 18, 2019 at 9:49

Lukasz Formela

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1 Comment

oracle02 Over a year ago

It worked, thank you. Thought it was way more complicated than that.

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