Filter object array based on string array "with partial match"

Question

I have an array of objects and want to filter it based on values of another string array and remove the objects that doesn't contain any of the strings.

I tried using split for the string array and search for each term in a forEach but it didn't work then tried the following which works as a filter but it filters for exact match not partial.

var employees = [
  {"name": "zxc asd", "age":"30"},
  {"name": "asd", "age":"24"},
  {"name": "qwe", "age":"44"},
  {"name": "zxc", "age":"28"},
];

var keepNames = ["asd", "qwe"];

keepNames = keepNames.map(name => {
  return name.toLowerCase();
});


var filteredEmployees = employees.filter(emp => {
  return keepNames.indexOf(emp.name.toLowerCase()) !== -1;
});

console.log( filteredEmployees );

Expected Output[  
  {"name": "zxc asd", "age":"30"},
  {"name": "asd", "age":"24"},
  {"name": "qwe", "age":"44"}];

Actual Output [
  {"name": "asd", "age":"24"},
  {"name": "qwe", "age":"44"}]

I'd really appreciate any help. Thanks in advance

btw, removeNames is misleading, becuase tis array has the keeping names. — Nina Scholz
– Nina Scholz, Commented Oct 5, 2019 at 16:52
yes i noticed after i posted the question, i used removeNames as i was trying the opposite at first then forgot to rename it. — A.O.G
– A.O.G, Commented Oct 5, 2019 at 17:05

Nina Scholz · Accepted Answer · 2019-10-05 16:59:39Z

4

You need to iterate the array with names keep as well and check the value.

var employees = [{ name: "zxc asd", age: "30" }, { name: "asd", age: "24" }, { name: "qwe", age: "44" }, { name: "zxc", age: "28" }],
    keep = ["asd", "qwe"],
    filtered = employees.filter(({ name }) =>
        keep.some(n => name.toLowerCase().includes(n))
    );

console.log(filtered);

.as-console-wrapper { max-height: 100% !important; top: 0; }

edited Oct 5, 2019 at 16:59

answered Oct 5, 2019 at 16:52

Nina Scholz

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Code Maniac · Accepted Answer · 2019-10-05 16:53:30Z

1

indexOf uses strict equality so it won't match partially.

You can use some and includes

var employees = [ {"name": "zxc asd", "age":"30"},{"name": "asd", "age":"24"},{"name": "qwe", "age":"44"},{"name": "zxc", "age":"28"},];
var filterBy = ["asd", "qwe"];

var filteredEmployees = employees.filter(emp => {
  return filterBy.some(v => emp.name.toLowerCase().includes(v.toLowerCase()))
});

console.log(filteredEmployees);

answered Oct 5, 2019 at 16:53

Code Maniac

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