Use "include" for ANY string in a array

Question

I have a search function that takes input/query text from a search bar. I want it to work for multiple search terms like "javascript react" or with more or less search terms. The input is saved in an array in state ("query") and compares to an object "workitem" and its property "description".

Let say:

   workitem.description.includes(this.state.query)

where

  this.state.query // = ["react", "javacript"]

Above will only work for certain situations. I want to see if the array/object includes ANY elements of the state. How to do it?

you can use indexof

Narendra Chouhan
– Narendra Chouhan

2019-10-10 11:03:36 +00:00
Commented Oct 10, 2019 at 11:03 — Narendra Chouhan
– Narendra Chouhan, Commented Oct 10, 2019 at 11:03

Horatiu Jeflea · Accepted Answer · 2019-10-10 11:37:54Z

2

// if needed, do a 
// if (!workitem.description || !this.state.query) {
//     return false;
// }

Considering description is an array:

return workitem.description.some(desc => this.state.query.indexOf(desc) >= 0)

Considering description is a string:

return workitem.description
    .split(' ')
    .some(desc => state.query.indexOf(desc) >= 0);

edited Oct 10, 2019 at 11:37

answered Oct 10, 2019 at 11:04

Horatiu Jeflea

7,4747 gold badges42 silver badges69 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Clarity Over a year ago

It seems description is a string not an array.

Horatiu Jeflea Over a year ago

let me do a version for both

Clarity · Accepted Answer · 2019-10-10 11:33:26Z

1

How about this:

workitem.description.split(' ').some(str => this.state.query.includes(str))

answered Oct 10, 2019 at 11:33

Clarity

10.9k2 gold badges27 silver badges38 bronze badges

Collectives™ on Stack Overflow

Use "include" for ANY string in a array

2 Answers 2

2 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related