How to avoid the php function call when passing a function variable?

Question

I have a function variable like this...

$aName = "My Name";

The function need to pass in like this:

$sayHelloFunction = function sayHello($aName){
       echo($aName);
}

Than, I have a method that responsible for execute the sayHelloFunction:

runningFunction($sayHelloFunction($aName));

in the runningFunction, it will have some condition to execute the function, but when I pass the "$sayHelloFunction($aName)" to runningFunction, it execute automatically, but I would like to pass the variable $aName as well, how can I achieve it? Thank you.

i think you are confusing php and javascript

Ibu
– Ibu

2011-05-01 08:29:22 +00:00
Commented May 1, 2011 at 8:29 — Ibu
– Ibu, Commented May 1, 2011 at 8:29
@Ibrahim - this is a perfectly valid PHP question.

Toby Allen
– Toby Allen

2011-05-01 08:31:28 +00:00
Commented May 1, 2011 at 8:31 — Toby Allen
– Toby Allen, Commented May 1, 2011 at 8:31

xconspirisist · Accepted Answer · 2011-05-01 08:29:24Z

2

runningFunction($sayHelloFunction, $aName);

Simples.

answered May 1, 2011 at 8:29

xconspirisist

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1 Comment

Tattat Over a year ago

but my sayHelloFunction requires param, and I don't want to assign the param inside the runningFunction.....

Lasar · Accepted Answer · 2011-05-01 12:11:51Z

1

You will have to pass the arguments separately. However, you could wrap them in an array so that you can pass them to runningFunction as a single argument, like this:

$printFunction = function($args) {
    print $args['lastname'].', '.$args['firstname'];
};

function runningFunction($f, $a) {
    $f($a);
}

$firstname = 'Bob';
$lastname = 'Smith';

$functionArguments = array(
    'firstname' => $firstname,
    'lastname' => $lastname
);

runningFunction($printFunction, $functionArguments);

~~If you want your dynamic functions to get "proper" arguments, then I see no way around something like this:~~

~~function runningFunction($f, $a) { switch(count($a)) { 0: $f(); break; 1: $f($a[0]); break; 2: $f($a[0], $a[1]); break; 3: $f($a[0], $a[1], $a[2]); break; // and so on } }~~

edited May 1, 2011 at 12:11

answered May 1, 2011 at 8:57

Lasar

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1 Comment

kapa Over a year ago

call_user_func_array() basically does what you did in your switch statement.

kapa · Accepted Answer · 2011-05-01 09:07:10Z

1

Pass the parameters as an array, and then use call_user_func_array() to call your function.

This way your runningFunction() will be absolutely abstract (as you requested), it can call any type of function, it's your responsibility to pass the right number of parameters.

function runningFunction ($callback, $parameters=array()) {
    call_user_func_array($callback, $parameters);
}

runningFunction($sayHelloFunction, array($aName));

call_user_func_array()

edited May 1, 2011 at 9:07

answered May 1, 2011 at 8:58

kapa

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Comments

Toby Allen · Accepted Answer · 2011-05-01 08:58:50Z

0

as xconspirisist suggested pass $aName as a seperate parameter to the function.

Details on Variable Functions can be found on the PHP site.

edited May 1, 2011 at 8:58

answered May 1, 2011 at 8:32

Toby Allen

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1 Comment

Tattat Over a year ago

I want to make the runningFunction abstract, that don't depends on the $sayHelloFunction, I don't mind pass runningFunction one more param, but I am considering, if I have one more param require, like $sayHelloFunctionAgain, which requires two params, $aName, $aTime, then, I need to write one more params for runningFunction, that is not wt I want....

Arjan · Accepted Answer · 2011-05-01 09:17:02Z

0

Use an anonymous function when calling runningFunction

function runningFunction($func) {
    $func();
}

runningFunction(function() {
    $sayHelloFunction($aName));
    // You can do more function calls here...
});

answered May 1, 2011 at 9:17

Arjan

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