Merge Objects: Problem with comparing and merge two objects in javascript

Question

Good night. Some charitable soul to help me with a problem about javascript objects. Thank you very much who can ...

var arrA = [
    {language:'php', count_access:5},
    {language:'c', count_access:7}
];

var arrB = [
    {language:'php', count_access:0},
    {language:'c', count_access:0},
    {language:'python', count_access:0},
    {language:'ace', count_access:0},
    {language:'electron', count_access:0},
];

var result = [...arrA, ...arrB].reduce((acc, item) => { 
    return item;
 }) ;

arrA.concat(result)

//How would you do for the output to be

/*[
{language:'php', count_access:5},
{language:'c', count_access:7},
{language:'python', count_access:0},
{language:'ace', count_access:0},
{language:'electron', count_access:0},
]*/

I'd use reduce like let result = [...arrA, ...arrB].reduce((acc, item) => { code here }, []) ... that should be enough to get you to write something for yourself — Bravo
– Bravo, Commented Oct 29, 2019 at 1:55
var arrA = [ {nome:'php', count:5}, {nome:'c', count:7} ]; var arrB = [ {nome:'php', count:0}, {nome:'c', count:0}, {nome:'python', count:0}, ]; var result = [...arrA, ...arrB].reduce((acc, item) => { return item; }, []) ; arrA.concat(result) — Taffarel Xavier
– Taffarel Xavier, Commented Oct 29, 2019 at 2:00
For example: var arrA = [ {nome:'php', count:5}, {nome:'c', count:7} ]; var arrB = [ {nome:'php', count:0}, {nome:'c', count:0}, {nome:'python', count:0}, {nome:'ace', count:0}, {nome:'electron', count:0}, ]; var result = [...arrA, ...arrB].reduce((acc, item) => { return item; }) ; arrA.concat(result) — Taffarel Xavier
– Taffarel Xavier, Commented Oct 29, 2019 at 2:05

Taffarel Xavier · Accepted Answer · 2019-10-29 02:37:30Z

2

This will work, it also adds up the counts for matching language

var arrA = [
    {language:'php', count:5},
    {language:'c', count:7}
];

var arrB = [
    {language:'php', count:0},
    {language:'c', count:0},
    {language:'python', count:0},
    {language:'ace', count:0},
    {language:'electron', count:0},
];

let result = [...arrA, ...arrB].reduce((acc, item) => {
  let found = acc.find(x => x.language=== item.language);
  if (found) {
    found.count += item.count;
  } else {
    acc.push(Object.assign({},item));
  }
  return acc;
}, [])
console.log(result);

edited Oct 29, 2019 at 2:37

Taffarel Xavier

5829 silver badges13 bronze badges

answered Oct 29, 2019 at 2:12

Bravo

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