How to run multiple js file using node js command line?

Question

I want to start 4 script using node js.

myapp
  -script1.js
  -script2.js
  -script3.js
  -app.js
  -package.json
  ....
  ....

I tried running it using below

node script1.js && node script2.js && node script3.js && node app.js

node script1.js & node script2.js & node script3.js & node app.js

But its not starting all script it only start script1.js.

How to do it ?

No actually my script files are services listening to specific code — user12290051
– user12290051, Commented Oct 31, 2019 at 7:21
It's difficult to answer without seeing the actual script. If all of them are independent scripts then please use the command I have mentioned in the answer below — Golak Sarangi
– Golak Sarangi, Commented Oct 31, 2019 at 7:23
simply use & instead of && as explained here :itnext.io/… worked for me on mac (node 14.7) — Hacke
– Hacke, Commented Aug 16, 2021 at 18:55

RoldanJr9711 · Accepted Answer · 2019-10-31 08:03:01Z

$ node script-1.js  && node script-2.js && node script-3.js && node app.js
I am script-1
I am script-2
I am script-3
I am app.js

It is working.

Maybe your script1.js is blocking those other scripts that are on the queue.

Node runs it in a synchronous way.

If you want to run those scripts in parallel.

You can use npm package called concurrently

In command line.

$ concurrently "node script-1.js" "node script-2.js" "node script-3.js" "node app.js"
[3] I am app.js
[2] I am script-3
[0] I am script-1
[1] I am script-2
[2] node script-3.js exited with code 0
[3] node app.js exited with code 0
[0] node script-1.js exited with code 0
[1] node script-2.js exited with code 0
Done in 1.07s.

Or you can put it on your package.json scripts.

"scripts": {
    "start": "concurrently \"node script-1.js\" \"node script-2.js\" \"node script-3.js\" \"node app.js\""
}

It will run multiple commands concurrently / in asynchronous way.

Hope it helps. :)

Golak Sarangi · Accepted Answer · 2019-10-31 07:21:22Z

1

Try this. it will execute all scripts irrespective of the exit code of the previous script

node script1.js; node script2.js; node script3.js; node app.js

answered Oct 31, 2019 at 7:21

Golak Sarangi

9078 silver badges23 bronze badges

1 Comment

user12290051 Over a year ago

I tried it give Error: Cannot find module 'D:\myapp\script1.js;'

Michael David · Accepted Answer · 2023-12-28 07:42:38Z

0

Use the pipe operator (windows). node service1.js | node service2.js

answered Dec 28, 2023 at 7:42

Michael David

1

Comments

Sayan Dey · Accepted Answer · 2024-01-04 07:00:06Z

0

you can use npm concurrently.

first install npm install -g concurrently

Then:

Run npm init to the parent directory of both of the projects.
the parent directory's package.json file will look like this.

{
  "name": "project",
  "version": "1.0.0",
  "description": "",
  "main": "index.js",
  "scripts": {
    "start": "concurrently \"npm run develop --prefix project1\" \"npm run develop --prefix project2\""
  },
  "author": "",
  "license": "ISC"
}

Then:

 write inside the "start" like above . just change the folder name of project1 and project2 with your projects name.

Then:

npm start

answered Jan 4, 2024 at 7:00

Sayan Dey

4825 silver badges13 bronze badges

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