converting string class name to an object in laravel

Question

i have this trait which i want to use dependency injection

<?php
 namespace App\Http\Controllers\Admin;
 trait ControllerTrait{


public function index($this->model $payroll){

    return $this->model->paginate(20);
   } 
}

the controller which uses this trait

namespace App\Http\Controllers\Admin;

use Illuminate\Http\Request;
use App\Http\Controllers\Controller;
use App\Payroll;

class PayrollController extends Controller
{
   use ControllerTrait;

   public $model = "Payroll";


 }

$model now is a string how to convert it to an object in calling index method of the trait

matticustard · Accepted Answer · 2019-11-27 19:59:45Z

1

I don't believe dynamic type-hinting is possible, nor is it necessary in this instance.

I imagine this is what you're looking for.

namespace App\Http\Controllers\Admin;

trait ControllerTrait{
    public function index() {
        return ('\App\\'.$this->model)::paginate(20);
    }
}

answered Nov 27, 2019 at 19:59

matticustard

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2 Comments

54ba Over a year ago

why can't i use return ($this->model)::paginate(20); public $model = App\Payroll::class it gives an error

matticustard Over a year ago

Try adding a preceding slash like public $model = \App\Payroll::class;. That works for me along with ($this->model)::paginate(20);.

Haq Nawaz · Accepted Answer · 2019-11-27 20:36:00Z

0

You can use "call_user_func" function which can call function in your model.

public $model = "Payroll";
call_user_func($model . "::index");

Hope this will help.

answered Nov 27, 2019 at 20:36

Haq Nawaz

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Comments

mod7ex · Accepted Answer · 2021-01-07 20:38:49Z

0

I think you can use it as a string in php

$controllerClassName = 'TODOS\CONTROLLERS\\' . ucfirst($this->_controller) . 'Controller';

which is a string and i used it to create instances

$controller = new $controllerClassName();

answered Jan 7, 2021 at 20:38

mod7ex

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