Include php preg_replace in string

Question

I am trying to include a php function within a string but my syntax is wrong. Could anyone help please?

$string = "<div id=\"apostnav\"><span class=\"calcir b-" . $string=get_field('br_category');
$string=preg_replace("/[^a-zA-Z]/", "", $string);
echo strtolower($string) . "></span></div>";

You can't define a new variable inside another variable definition. — user2342558
– user2342558, Commented Dec 2, 2019 at 11:12
@user2342558 although meaningless (the value of $string is immediately overwritten) that is perfectly valid PHP. 3v4l.org/tuZTh — Nick
– Nick, Commented Dec 2, 2019 at 11:43
@user2342558 I do think your answer is actually what OP wants, it's just that statement which is incorrect. — Nick
– Nick, Commented Dec 2, 2019 at 11:55

user2342558 · Accepted Answer · 2019-12-02 11:56:08Z

2

Try this:

$string=get_field('br_category');
$string=preg_replace("/[^a-zA-Z]/", "", $string);

$string = "<div id=\"apostnav\"><span class=\"calcir b-" . strtolower($string) . "\"></span></div>";

I moved up two lines of code andn removed an echo from the last one.

Here the code with few optimizations:

$string = get_field('br_category');
$string = preg_replace("/[^a-zA-Z]/", '', $string);
$stringLower = strtolower($string);

$string = "<div id='apostnav'><span class='calcir b-$stringLower'></span></div>";

edited Dec 2, 2019 at 11:56

answered Dec 2, 2019 at 11:13

user2342558

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marcell · Accepted Answer · 2019-12-02 11:51:36Z

1

You can use printf too in order to print your html string with the variable:

printf('<div id="apostnav"><span class="calcir b-%s"></span></div>', strtolower(preg_replace('/[^a-zA-Z]/', '', get_field('br_category'))));

answered Dec 2, 2019 at 11:51

marcell

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