I have to initialize class with list, which will return every sublists from the given list.
I have a problem with defining empty list as an argument:
class list():
def sublists(self, lst=[]):
sub = [[]]
for i in range(len(lst)+1):
for j in range (i+1, len(lst)):
sub = lst[i:j]
sub.append(sub)
return sub
As others have pointed out, your intention is not quite clear from the question. What I understood is that you want to get all contiguous sublists of a given list.
This achieves that.
class MyList:
def sublists(self, lst=[]):
subs = [[]]
for i in range(len(lst)):
for j in range (i+1, len(lst)+1):
sub = lst[i:j]
subs.append(sub)
return subs
x = [i for i in range(3)]
my_list = MyList()
print(my_list.sublists(x))
Please update your question if you intend to do something else.
Correct me if I'm wrong, but I guess the task is quite simple. You can just init your class instance with the list:
class list():
sub = []
def __init__(self, lst=[]):
self.sub = lst
a = [
[1,2,3],
[4,5,6],
[7,8,9],
]
myClass = list(a)
print(myClass.sub)
listas a name for a class, that will shadow the built-in namelist