How to find element by part of its id name in selenium with python

Question

I'm using selenium with python,now I want to locate an element by part of its id name,what can I do?

For example,now I've already located a item by id name coption5 :

sixth_item = driver.find_element_by_id("coption5")

Is there anyway I can locate this element only by using coption?

Use XPATH's "contains" method: guru99.com/xpath-selenium.html#6 — browsermator
– browsermator, Commented Jan 7, 2020 at 22:44
@Guy This question is all about locators Xpath and Css, any reason why you want to hide the question from Xpath and Css contributors removing those tags? — undetected Selenium
– undetected Selenium, Commented Jan 8, 2020 at 6:45
@DebanjanB Using xpath and css_selector is the solution, not the question. — Guy
– Guy, Commented Jan 8, 2020 at 7:20
@Guy So what do you feel the question was all about :) Does Selenium have any other way other then Css and Xpath — undetected Selenium
– undetected Selenium, Commented Jan 8, 2020 at 7:23

undetected Selenium · Accepted Answer · 2021-01-26 19:05:39Z

27

To find the element which you have located with:

sixth_item = driver.find_element_by_id("coption5")

To locate this element only by using coption you can use can use either of the following Locator Strategies:

Using XPATH and starts-with():

sixth_item = driver.find_element_by_xpath("//*[starts-with(@id, 'coption')]")

Using XPATH and contains():

sixth_item = driver.find_element_by_xpath("//*[contains(@id, 'coption')]")

Using CSS_SELECTOR and ^ (wildcard of starts-with):

sixth_item = driver.find_element_by_css_selector("[id^='coption']")

Using CSS_SELECTOR and * (wildcard of contains):

sixth_item = driver.find_element_by_css_selector("[id*='coption']")

Reference

You can find a detailed discussion on dynamic CssSelectors in:

answered Jan 7, 2020 at 23:17

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Thank you so much for your reply,but in my situation it doesn't work now.I'll keep trying!

It is so useful!Thank you so much!