Get information from a numpy array

Question

I have a numpy array which is 5 by 182 that looks similar to something like this:

matched_data = '/home/myname/data.csv'
matched_data = Table.read(matched_data, format="ascii")

ID_1 = np.array(matched_data['name'])
ID_1.astype(str)

ID_2 = np.array(matched_data['col1_1'])
ID_2.astype(str)

mag = np.array(matched_data['Magnitude'])
mag.astype(float)

semi_major_axis = np.array(matched_data['SMA'])
semi_major_axis.astype(float)

semi_minor_axis = np.array(matched_data['sma'])
semi_minor_axis.astype(float)

position_angle = np.array(matched_data['pos_ang'])
position_angle.astype(float)


match = (ID_1, ID_2, mag, (semi_major_axis/semi_minor_axis), position_angle)
match = np.array(match)

How would I be able to get data out of this line by line? For example when I type :

print(match[0])

it prints out the list of IDs from ID_1 where as I would like the ID_1, ID_2, magnitude, (semi_major_axis/semi_minor_axis) and position_angle of the first object. How would I do this?

a_guest · Accepted Answer · 2020-02-10 11:45:37Z

2

Instead of match = np.array(match) you can use match = np.stack(match, axis=1). This way the various quantities (ID_1, ID_2, mag, ...) will be columns of the resulting array and you can access them via match[index]. If you did np.stack(match, axis=0) then this is similar to what you did originally and the data will be rows in the resulting array. Here it's still possible to access it by providing a column index: match[:, 0].

answered Feb 10, 2020 at 11:45

a_guest

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