Python - Return true if strings found in nested list

Question

My goal is to return True/False if I am able to detect two items within a nested list.

E.g.

list1 = [['1', 'sjndnjd3', 'MSG1'], ['2', 'jdakb2', 'MSG1'], ['1', 'kbadkjh', 'MSG2']]

I want to iterate over this list to confirm if I can find '1' & 'MSG1' within a nested list. Important to note I only want this to return true if both items are found and if they're found within the same nested list.

I've tried various combinations of the below however I cannot get it quite right.

all(x in e for e in list1 for x in ['1', 'MSG1'])

Any assistance is greatly appreciated.

Do you want to match two items within same group or is matching in different group is also required? — AKS
– AKS, Commented Mar 14, 2020 at 5:48
In the above instance, both '1' and 'MSG1' need to be within the same nested list. E.g. only list1[0] should match. In the event that list1 only contained list1[1] & list1[2], this should return false. — ditrapanij
– ditrapanij, Commented Mar 14, 2020 at 5:49

Shubham Sharma · Accepted Answer · 2020-03-14 05:51:21Z

2

Try this:

contains = any([True for sublist in list1 if "1" in sublist and "MSG1" in sublist])

answered Mar 14, 2020 at 5:51

Shubham Sharma

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Comments

AKS · Accepted Answer · 2020-03-14 05:54:33Z

1

You can use set.issubset:

any(True for sub_list in list1 if {'1', 'MSG1'}.issubset(set(sub_list)))

answered Mar 14, 2020 at 5:54

AKS

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Nick · Accepted Answer · 2020-03-14 06:45:34Z

1

You need to apply all to each test of 1 and MSG being in list1, so you need to rewrite your list comprehension as

found = [all(x in e for x in ['1', 'MSG1']) for e in list1]
# [True, False, False]

You can then test for any of those values being true:

any(found)
# True

edited Mar 14, 2020 at 6:45

answered Mar 14, 2020 at 5:55

Nick

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1 Comment

ditrapanij Over a year ago

Thanks for the explanation!

revliscano · Accepted Answer · 2020-03-14 06:03:58Z

0

You can make a function as follows, using sum and list's count method:

def str_in_nested(list_, string_1, string_2):
    return sum(sub_list.count(string_1) and sub_list.count(string_2) for sub_list in list_) > 0

Applying this function to you current case:

>>> list1 = [['1', 'sjndnjd3', 'MSG1'], ['2', 'jdakb2', 'MSG1'], ['1', 'kbadkjh', 'MSG2']]
>>> str_in_nested(list1, '1', 'MSG1')
True

edited Mar 14, 2020 at 6:03

answered Mar 14, 2020 at 5:58

revliscano

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VPfB · Accepted Answer · 2020-03-14 06:14:53Z

0

It's:

any(all(item in sublist for item in ['1', 'MSG1']) for sublist in list1)

answered Mar 14, 2020 at 6:14

VPfB

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revliscano · Accepted Answer · 2020-03-15 18:16:15Z

0

Give this a try...

for item in list1:
    all(i in item for i in sub)

edited Mar 15, 2020 at 18:16

revliscano

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answered Mar 14, 2020 at 6:20

Charlton Figueira

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