In the image above I am trying to click the 'Continue with email' button. This is the code I have:
from selenium import webdriver
Driver = webdriver.Firefox() #Define webdriver to use
Driver.get('https://www.airbnb.co.uk/login')
Element = Driver.find_element_by_xpath("//div[contains(@class,'_p03egf') and (@class, '_18m31f1b')]")
Element.click
Either my syntax is wrong or my poor understanding of web pages is letting me down
Any help - much appreciated
Thanks Rob
You can use below solutions, if you want to click on a Continue with email button:
- XPATH
Example 1
wait = WebDriverWait(Driver, 30)
wait.until(EC.presence_of_element_located((By.XPATH, "//div[contains(text(),'Continue with email')]"))).click()
Example 2
wait = WebDriverWait(Driver, 30)
wait.until(EC.presence_of_element_located((By.XPATH, "//div[@class='_bc4egv gs_copied']"))).click()
- CSS Selector
wait = WebDriverWait(Driver, 30)
wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, ".\_18m31f1b:nth-child(1) .\_bc4egv"))).click()
Dont forget to add below imports
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
I think your XPath is off, from the example you gave, I would assume you want something like this:
Element = Driver.find_element_by_xpath("//button[@data-testid='social-auth-button-email']")
w3schools.com has a great tutorial on XPath syntax
Can you try this code
Element = Driver.find_element_by_xpath('//*[@id="site-content"]/div/div/div/div/div/div/div/div[2]/button')
find_elements_by_class_name('_18m31f1b').click()
It should be enough to do what you want as the button seems to be connected to that class and all you want to do is click it.
