jquery .load() with multiple variables

Question

I am using the jquery .load() method for a search. I have figured out how to send one variable, but I need to send many.

WITH ONE

var field1 = ($('#form1 input[name="field1"]:text').val());
$('#results').load("/search/show.php", {field1: field1});

How would I do two variables? THIS WONT WORK

var field1 = ($('#form1 input[name="field1"]:text').val());
var field2 = ($('#form1 input[name="field2"]:text').val());
$('#results').load("/search/show.php", {field1: field1}{field2: field2});

I'm sure there is an easy way to send multiple variables, I just don't know how!

Andrew Whitaker · Accepted Answer · 2011-05-24 02:39:41Z

7

You're looking for:

var field1 = ($('#form1 input[name="field1"]:text').val());
var field2 = ($('#form1 input[name="field2"]:text').val());
$('#results').load("/search/show.php", {field1: field1, field2: field2});

Check out object literals on the MDC.

answered May 24, 2011 at 2:39

Andrew Whitaker

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1 Comment

livinzlife Over a year ago

Thanks for the help and thanks so much for the reference, it will be very helpful in the future!

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