how to print a string array elements in a label ? c#

Question

My problem is common which is to print an array elements inside a label in windows form with c# but I wanted to use if statement to print a certain elements not all the elements , the code has two forms :

form 1 :

public static String [] names = new String [3];
private void button (sender and whatever ...){

      if(label1.Text.Equals("meal1")){
         names[0] = "name1";
      }
      if(label1.Text.Equals("meal2")){
         names[1] = "name2";
      }
      if(label1.Text.Equals("meal3")){
         names[2] = "name3";
      }
      this.Hide();
      Form2 frm2 = new Form2();
      frm2.Show();
}

I did this to send the array data to the next form , the elements of the array are stored depending on user choice from a menu

form 2 :

private void Form2_Load(...){

    String [] names2 = {"name1" , "name2" , "name3"};

    for(int i = 0 ; i < Form1.names.Length ; i++){
        if(Form1.names[i].Equals(names2[i])){
             label1.Text = names2[i] + "\n";
        }
    }

}

lets say user chooses "meal1" and "meal3" , now when form 2 is loaded I must see "meal1" and "meal3" in the label but all I see is the last choice of the user , I tried String.join("\n",names2[i]); but it printed all the array elements I tried labe1.Text += names2[i] + "\n"; it also prints the last choice for the user.

thank you ...

You need to use += operator instead of = in this line label1.Text += names2[i] + "\n"; — Salah Akbari
– Salah Akbari, Commented Apr 9, 2020 at 10:46
Holger , thanks for the info , maybe because am working with java mostly we use the phrase "print" a lot is there an alternative to this phrase ? — Mazen Al-ali
– Mazen Al-ali, Commented Apr 9, 2020 at 19:02
@SalahAkbari , it worked well thank you , but null pointer problem appears any ideas ? — Mazen Al-ali
– Mazen Al-ali, Commented Apr 9, 2020 at 19:04

FAHAD SIDDIQUI · Accepted Answer · 2020-04-09 11:01:30Z

2

Yah, I got your problem. every time you run your code you will get the last name whose condition will be true. Here is solution to your problem.

if(Form1.names[i].Equals(names2[i])){
         label1.Text = names2[i] + "\n";
    }

In these lines, you are just assigning the name to label1 but every time you assign a new value, the old value is replaced. You should change this assignment line as

if(Form1.names[i].Equals(names2[i])){
         label1.Text += names2[i] + "\n";
    }

answered Apr 9, 2020 at 11:01

FAHAD SIDDIQUI

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2 Comments

Mazen Al-ali Over a year ago

thank you it worked but another problem appeared which is the null pointer ... is there any null pointer here ?

FAHAD SIDDIQUI Over a year ago

Null pointer exception occurs when you overrun loop. Change your for loop as following: ............................... for(int i = 0 ; i < .names2.Length ; i++){

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