JavaScript: How to split string into array based on a curly-braces-pattern?

Question

I want to split a string similar to this:

"2*{some_string}*8*{some_other_string}"

Into an array, keeping the curly braces intact:

["2*","{some_string}","*8*","{some_other_string}"]

I'm hitting a wall and always end up remove the curly braces. Any clues out there?

I've been working with something like this:

var found = [],          // an array to collect the strings that are found
    rxp = /{([^}]+)}/g,
    str = "a {string} with {curly} braces",
    curMatch;

while( curMatch = rxp.exec( str ) ) {
    found.push( curMatch[1] );
}

console.log( found );    // ["string", "curly"]

Thanks :)

what have you tried so far ? please post the code

Code Maniac
– Code Maniac

2020-04-15 05:32:32 +00:00
Commented Apr 15, 2020 at 5:32 — Code Maniac
– Code Maniac, Commented Apr 15, 2020 at 5:32
Updated my post above :)

Lasse van den Bosch Christense
– Lasse van den Bosch Christense

2020-04-15 06:04:46 +00:00
Commented Apr 15, 2020 at 6:04 — Lasse van den Bosch Christense
– Lasse van den Bosch Christense, Commented Apr 15, 2020 at 6:04

lhoro · Accepted Answer · 2020-04-15 06:25:08Z

3

Don't really need replace. You can keep the {} when you split it by using regex, but it will create empty string, so you will need to use filter to remove empty string in the array after splitting.

console.log("2*{some_string}*8*{some_other_string}".split(/({.*?})/).filter(s => !!s))

edited Apr 15, 2020 at 6:25

answered Apr 15, 2020 at 6:19

lhoro

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