Can I define both function's argument's default value and data type in python? [duplicate]

Question

I want to write something like this.

def func_name(arg1, arg2, arg3 = 3) #this defines default value for optional argument arg3
def func_name(arg1, arg2, arg3: int) #and this defines data type for required argument arg3

Is there any possible method to define both of them? Something like this

def func_name(arg1, arg2, arg3 = 3: int)

Does this answer your question? Adding default parameter value with type hint in Python — chash
– chash, Commented May 19, 2020 at 14:17

ojdo · Accepted Answer · 2022-12-09 15:01:14Z

23

You can use like this.

def boo(arg1, arg2, arg3: int = 10):
    ....

ojdo

9,1258 gold badges43 silver badges66 bronze badges

answered May 19, 2020 at 14:17

Chih Sean Hsu

4332 silver badges11 bronze badges

Sign up to request clarification or add additional context in comments.

1 Answer 1