sorting input numbers in ascending order in python

Question

name = int(input('>>>'))
ascending_order = name.split(', ')
ascending_order.sort()
print(ascending_order)

I am having error in line 1: int(input(">>>")

name = int(input('>>>')) ValueError: invalid literal for int()

I bet you’re typing numbers separated by a comma. If so, a comma cannot be converted to an int so do the conversion after / during the split. — s3dev
– s3dev, Commented Jun 2, 2020 at 13:15
If the input is a comma-delimited list of numbers, you can't have int() applied to the input. You need name = input('>>>'). You need to then convert each element of ascending_order to an int after the split. — DarrylG
– DarrylG, Commented Jun 2, 2020 at 13:19
Why are you casting the input to an integer? If you want to split something, you need to be using a string, str(input('>>>') — I_keep_getting_downvoted
– I_keep_getting_downvoted, Commented Jun 2, 2020 at 13:19
@I_keep_getting_downvoted: The str is implied and not needed. — s3dev
– s3dev, Commented Jun 2, 2020 at 13:21

Ali Hassan · Accepted Answer · 2020-06-02 14:57:54Z

1

with string conversion into integer:

name = input('>>>')
ascending_order = name.split(',')
for i in range(len(ascending_order)):
     ascending_order[i] = int(ascending_order[i])
ascending_order = sorted(ascending_order, reverse=True)
print(ascending_order)

without string conversion into integer:

name = input('>>>')
ascending_order = name.split(',')
ascending_order = sorted(ascending_order, reverse=True)
print(ascending_order)

answered Jun 2, 2020 at 14:57

Ali Hassan

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2 Comments

s3dev Over a year ago

What about something more concise like: asc = sorted([int(i) for i in name.split(‘,’)])?

Ali Hassan Over a year ago

You did the same thing but the technique you have used is list comprehension. and one more thing now its fine asc = sorted([int(i) for i in name.split(',')], reverse=True) .

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