i'm new at this forum and php. I want to show some info when the script detects one or more words in the postname (Wordpress) In my exapmle like to dispaly extra info when Omnik + reset or wifi is detected.
I like to know how i can simplify the following code:
$url = "www.myurl.nl/postname"
if (strpos($url, 'omnik' )!==false){
echo "Omnik";
}
else if (strpos($url, 'reset' )!==false){
echo "Reset";
}
else if (strpos($url, 'wifi' )!==false){
echo "Wifi";
}
else {
echo "No Omnik,Reset or Wifi there";
}
At this moment i can only show the extra info when the word "Omnik" is detected. Example: https://geaskb.nl/omnik shows the extra info, but https://geaskb.nl/omnik-reset and https://geaskb.nl/omnik-wifi should show the info too, while https://geaskb.nl/solaredge shouldn't show the info.
Hope you get what i mean.
====== Added 20:00 ========
Hi All, thanks for the ansewers. I should have be clear the 1st time i guess. This is the code i use now:
// Verkrijg URL incl. subdir.
if(isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] === 'on')
$geturl= "https";
else
$geturl = "http";
// Here append the common URL characters.
$geturl .= "://";
// Append the host(domain name, ip) to the URL.
$geturl .= $_SERVER['HTTP_HOST'];
// Append the requested resource location to the URL
$geturl .= $_SERVER['REQUEST_URI'];
if (strpos($_SERVER['REQUEST_URI'], "omnik" )!==false){
echo "Omnik in url";
}
else {
echo "Geen Omnik in $geturl";
}
============= 20:30u ================== Problem solved!! stripos solved the problem! Thanks for all your help!