Delete or filter an object in a nested array (Javascript)

Question

Based on an array like this:

 var p = [
           {x: [
                 {x1: 1}, 
                 {x1: 2},
               ]
           },
         ];

How can I get something like this:

// Result of filtering an object where key is 'x1' and value is greater than 1
p === [
        {x: [
              {x1: 2},
            ]
        },
      ];

Rubydesic · Accepted Answer · 2020-07-12 23:17:29Z

1

p = p.map(v => {
    v.x = v.x.filter(({ x1 }) => x1 > 1)
    return v
})

or (shorter syntax)

p = p.map(v => (v.x = v.x.filter(({ x1 }) => x1 > 1), v))

answered Jul 12, 2020 at 23:17

Rubydesic

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Comments

andai · Accepted Answer · 2020-07-12 23:21:08Z

0

to create a new array q with the desired properties

var q = [
    {x: p[0].x.filter( (x) => x.x1 > 1 ) }
]

or if you wish to change the array p in place

p[0].x = p[0].x.filter( (x) => x.x1 > 1 )

answered Jul 12, 2020 at 23:21

andai

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Comments

sonEtLumiere · Accepted Answer · 2020-07-12 23:26:26Z

0

This code will return an array of objects with property 'x1' greater than 1.

var p = [{x: [{x1: 1}, {x1: 2}]}];

let filtered = p.map(obj => obj.x.filter(y => y.x1 > 1));
console.log(filtered);

answered Jul 12, 2020 at 23:26

sonEtLumiere

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Comments

Matt · Accepted Answer · 2020-07-12 23:26:33Z

0

var result = p[0].x.find(x = x.x1 > 1)

answered Jul 12, 2020 at 23:26

Matt

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1 Comment

Lian Nivin Over a year ago

It is a very short answer but you could replace [0] for a generic response. Thanks anyway.

Sven.hig · Accepted Answer · 2020-07-12 23:49:40Z

0

use map and filter

var p = [
  {x: [{x1: 1}, {x1: 2}]},
];
result=p.map((o)=>({...o.x.filter(y=>y.x1>1)}))
console.log(result)

edited Jul 12, 2020 at 23:49

answered Jul 12, 2020 at 23:32

Sven.hig

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