How to join fields of an array of objects in javascript/typescript

Question

I have an array like this

const array = [{a: '1', b: '2'}, {a: '3', b: '4' }];

I want to join the only field into a string to have a result like this: '1, 3'

The join function of an array can only be used on the whole entry, not on fields of the object that is underneath. Is there a way to do this with standard functionality or do I have to use a for loop or a forEach?

you'll need a loop, I'd go for a .map

jonatjano
– jonatjano

2020-07-31 12:23:54 +00:00
Commented Jul 31, 2020 at 12:23 — jonatjano
– jonatjano, Commented Jul 31, 2020 at 12:23

Nikita Madeev · Accepted Answer · 2020-07-31 12:23:56Z

8

Before join you need map array

const array = [
    { a: '1', b: '2' },
    { a: '3', b: '4' },
];

const result = array.map(_ => _.a).join(', ');

console.log(result);

answered Jul 31, 2020 at 12:23

Nikita Madeev

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HamzaMushtaq · Accepted Answer · 2020-07-31 12:51:14Z

0

In order to perform this through For loop.

result = [];
const array = [{ a: '1', b: '2' }, { a: '3', b: '4' }];
array.forEach(elm => result.push(elm.a));
console.log(result.join(", "));
// 1, 3

answered Jul 31, 2020 at 12:51

HamzaMushtaq

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