HTML to PHP form data not submitting

Question

I want to pass information from an HTML form to a PHP page. My problem is that the data from the form is not getting submitted. What am I doing wrong ?

HTML FORM

<div id="go">
    <form method="get" action="client_authorized.php">
        <fieldset>
            <input type="text" name="query" class="input-text" />
            <input type="submit" value="Secure Client Access" class="input-submit" />
        </fieldset>
    </form>
</div>

client_authorized.php

<?php
     print $_GET['query'];
?>

Why have you put your submit button inside another form? When you submit it from that form, you lose data set in other forms. — tomsseisums
– tomsseisums, Commented Jun 13, 2011 at 14:22

Michael Berkowski · Accepted Answer · 2011-06-13 14:22:14Z

5

Your submit button is wrapped in another <form>. This should be an <input type='submit'> instead. Just remove the extra <form></form>.

<div id="go">
  <form method="get" action="client_authorized.php">
    <fieldset>
        <input type="text" name="query" class="input-text" />
        <input type="submit" value="Secure Client Access" class="input-submit" />
    </fieldset>
  </form>
</div>

answered Jun 13, 2011 at 14:22

Michael Berkowski

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2 Comments

Vinoth Over a year ago

Hi Michael...I tried it it still didn't work. Am I making an error elsewhere ?

Michael Berkowski Over a year ago

@Vinoth You are certain PHP is functioning properly otherwise? Do you get anything if you print_r($_GET); to dump the contents of the GET vars?

tomsseisums · Accepted Answer · 2011-06-13 14:36:56Z

4

<div id="go">
    <!-- see the moved `target` attribute from other form element to here -->
    <form target="_blank" method="get" action="client_authorized.php">
        <fieldset>
            <input type="text" name="query" class="input-text" />
            <!-- <form target="_blank"> -->
            <input type="submit" value="Secure Client Access" class="input-submit" />
            <!-- </form> -->
            <!-- this form here is as useless as these comments are, define target in main form -->
        </fieldset>
    </form>
</div>

Basicly your second <form/> overrides first <form/> elements, therefore loses data when posted.

Oh, by the way PHP's print(); won't print out your array data (at least I think so..), you should use print_r(); or var_dump(); instead.

edited Jun 13, 2011 at 14:36

answered Jun 13, 2011 at 14:25

tomsseisums

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2 Comments

Vinoth Over a year ago

Tom did as you said. It works thanks...human error is always redundant :)

tomsseisums Over a year ago

My guess would be that @Michael's solution didn't work because of the lost target attribute on <form/> element. Altho', not 100% sure. It could be possible that when passing elements through $_GET not $_POST, data is lost when posted outside PHP_SELF - blank window.

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