Conversion: Array to Json automatically

Question

How to make this script automatically concatenate the array? So that it is not necessary to pass the indices, example: arr[0] ... arr[n]. Where val1, val2 ... val(n), is automatically assigned in an increasing way, example: val1, val2, val3 ... and so on. That way the array could have N values and all would be transformed into Json automatically

import json

arr = ['MyValue1', 'MyValue2']
list = [{"labels": {"val1": arr[0], "val2": arr[1]}}]

print(json.dumps(list))

Output:

{
    "labels": {
        "val1": "MyValue1",
        "val2": "MyValue2"
    }
}

That doesn't seem like a good idea. Why not store the labels as a list? — superb rain
– superb rain, Commented Aug 18, 2020 at 13:18
Why not use this JSON output instead? {"labels": ["MyValue1", "MyValue2"]} — Thomas
– Thomas, Commented Aug 18, 2020 at 13:21
{"labels": ["MyValue1", "MyValue2", "MyValue3"]} of course. Or in general: json.dumps({"labels": arr}). — Thomas
– Thomas, Commented Aug 18, 2020 at 13:25

mahdilamb · Accepted Answer · 2020-08-18 13:31:55Z

2

You could use dictionary comprehension:

import json

arr = ['MyValue1', 'MyValue2']
list = [{"labels": {"val%d"%(i+1):e for i,e in enumerate(arr)}}]

print(json.dumps(list))

Alternatively:

import json

arr = ['MyValue1', 'MyValue2']
list = {"labels": arr}

print(json.dumps(list))

edited Aug 18, 2020 at 13:31

answered Aug 18, 2020 at 13:23

mahdilamb

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7 Comments

Luis Henrique Over a year ago

Perfect, I just wanted a performatic way to do that, thanks!

mahdilamb Over a year ago

No problem. An alternative would be to do something like this list = [{"labels": arr}] You can have ordered lists in json, so there isn't a need to have a new dictionary. Of course, either option is fine

Luis Henrique Over a year ago

Anyway, could you attach the other option to your answer? We leave it to people in the future with the same doubt to decide which approach they think is best to follow for their problem

mahdilamb Over a year ago

@LuisHenrique dictionary comprehension is an extra operation and an extra data structure, so I would say it is better to just have the list in the dictionary. You could also get rid of the square brackets as Thomas suggested in their comment as you can dump a dictionary with json

mahdilamb Over a year ago

@LuisHenrique I shall do

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