I have defined the class A in Scala:
class A(var number: Int)
But when I try to access its member field number in java, I get an error:
A a = new A();
a.number = 4;
Results in: java: number has private access in A.
If I try to access the number from scala, there is no problem.
What can I do to get around this issue?
Use getter
a.number();
and setter
a.number_$eq(4);
instead of the field itself a.number.
Or
a.getNumber();
a.setNumber(4);
if you annotate the field
import scala.beans.BeanProperty
class A(@BeanProperty var number: Int)
If I try to access the
numberfrom scala, there is no problem.
In Scala when you write a.number or a.number = 4 you actually call getter/setter (this is syntax sugar).
You can look at the generated class file when you compile A.scala, that can explain getter number() and setter method number_$eq from Dmytro's answer
// A.scala
class A(var number: Int)
> scalac A.scala
> javap -p A.class
// output of above step
public class A {
private int number;
public int number();
public void number_$eq(int);
public A(int);
}
