Conditional replacing in a string - Python

Question

I am very new to Python and programming. I have a file with measurment values that looks like this:

85.2147....85.2150..85.2152..85.2166...85.2180.85.2190.

At the end what I want to have is:
85.2147
85.2150
85.2152
85.2166
85.2180
85.2190

What I managed using

k = (j.replace('....', '\r'))
l = (k.replace('...', '\r'))
m = (l.replace('..', '\r'))

is this:

85.2147
85.2150
85.2152
85.2166
85.2180.85.2190.

Now, the question is, how can I conditionally replace single dots, A) if no numbers come after it; and B) if the number after the point is the same as the 6th number (or 7th character) before the point.

Use regex module

Bera
– Bera

2020-09-11 09:42:49 +00:00
Commented Sep 11, 2020 at 9:42 — Bera
– Bera, Commented Sep 11, 2020 at 9:42

Anjaly Vijayan · Accepted Answer · 2020-09-12 03:11:47Z

1

>>> import re
>>> string = '85.2147....85.2150..85.2152..85.2166...85.2180.85.2190.'
>>> result = re.findall('(\d+\.\d+)\.+',string)
>>> result
['85.2147', '85.2150', '85.2152', '85.2166', '85.2180', '85.2190']

answered Sep 12, 2020 at 3:11

Anjaly Vijayan

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Comments

Ian Turton · Accepted Answer · 2020-09-11 09:45:41Z

1

You should read up on Python regular expressions and book mark a regular expression test page to help you solve these problems. Also, it's good to remember that Python can be run in interactive mode to allow you to test things out by hand very quickly.

>>> import re
>>> test = "85.2147....85.2150..85.2152..85.2166...85.2180.85.2190."
>>> target = re.compile(r'(\d+\.\d+)(\.+)')
>>> match = re.findall(target, test)
>>> match
[('85.2147', '....'), ('85.2150', '..'), ('85.2152', '..'), ('85.2166', '...'), ('85.2180', '.'), ('85.2190', '.')]
>>> res
['85.2147', '85.2150', '85.2152', '85.2166', '85.2180', '85.2190']
>>>

answered Sep 11, 2020 at 9:45

Ian Turton

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