How to pass a list of strings from python to shell script?

Question

I need to pass a list of strings from python to shell script.

Goal: Inside the Shell script,

1)The shell script should accept that list of strings which is passed as a parameter.

2)I need to loop that list and print the strings inside the loop.

What I had tried:

main.py

import subprocess
ssh_key_path = #KEY_PATH
ip_address = #BASTION_IP
Details = #Somedata
list_1 = ["apple","banana","carrot"]
script = subprocess.call([sh,fruits.sh,ssh_key_path,ip_address,Details,list_1])

fruits.sh

ssh -i $1 ubuntu@$2 -o StrictHostKeyChecking=no << EOF
   printf $3 >/home/Details.txt
   fruits = $4
   for i in $4; do
     echo "$i"
   done
   echo "Success" 
EOF

Output from fruits.sh:(Expected Output)

apple
banana
carrot
Success

Error: expected str, bytes, or os.PathLike object, not list.

So,How to pass the list to shell script and execute inside it.?

alani · Accepted Answer · 2020-09-29 09:24:12Z

Just join with spaces. For example:

test.py

import subprocess

fruits = ["apple","banana","carrot"]

subprocess.call(["sh", "test.sh", "hello", " ".join(fruits)])

test.sh

echo "greeting: $1"

for i in $2
do
    echo "fruit: $i"
done

Output:

greeting: hello
fruit: apple
fruit: banana
fruit: carrot

The basic point here is that you are passing a single string argument, and your shell script is then splitting it as required.

But if you cannot use space as a separator, then you will have to use multiple arguments. For example:

test.py

import subprocess

fruits = ["green apple", "yellow banana", "orange carrot"]

subprocess.call(["sh", "./test.sh", "hello"] + fruits)

test.sh

echo "greeting: $1"

shift

for i in "$@"
do
    echo "fruit: $i"
done

output:

greeting: hello
fruit: green apple
fruit: yellow banana
fruit: orange carrot

Here the shift in the shell script will drop the first argument from the argument list, so that the "$@" will loop over the remaining arguments. (Repeat shift as many times as necessary.)

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