Reverse array NOT using reverse

Question

I am looking for a way to get my array to create a new array, with numbers in reverse without using the reverse method.

e.g.

let numbers = [1, 2, 3]
console.log(reverse(numbers))

should return “[3, 2, 1]”.

Thanks

Please try instead of reverse(numbers) this numbers.reverse(); — Waqar Akram
– Waqar Akram, Commented Oct 12, 2020 at 11:11
const numbers = [1, 2, 3, 4, 5, 6]; const result = numbers.reduce((a, b) => [b].concat(a), []); — Ricardo Sanchez
– Ricardo Sanchez, Commented Oct 12, 2020 at 11:31

Ilijanovic · Accepted Answer · 2020-10-12 11:06:04Z

2

Here. A quick solution with map. returns you new array

let numbers = [1, 2, 3]

let result = numbers.map((el, i, arr) => arr[arr.length - 1 - i])

console.log(result)

answered Oct 12, 2020 at 11:06

Ilijanovic

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Comments

Rezaa91 · Accepted Answer · 2020-10-12 11:07:49Z

2

Here is a quick way using a standard for loop

const numbers = [1, 2, 3]
const reverse = [];

for (let i = numbers.length - 1; i >= 0; i--) {
    reverse.push(numbers[i])
}

console.log(reverse);

answered Oct 12, 2020 at 11:07

Rezaa91

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Iosif · Accepted Answer · 2020-10-12 11:08:57Z

2

Short and simple:

let numbers = [1, 2, 3, 4];
const reverse = (array) => array.map(array.pop, [...array]);
console.log(reverse(numbers));

answered Oct 12, 2020 at 11:08

Iosif

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