compare multiple array of objects javascript with the value

Question

let a = [{
    isMatched: false,
    value: 'red'
}, {
    isMatched: false,
    value: 'green'
}];
let b = [{
    isMatched: false,
    value: 'red'
}, {
    isMatched: false,
    value: 'brown'
}];
let c = [{
    isMatched: false,
    value: 'white'
}, {
    isMatched: false,
    value: 'green'
}];
let d = [{
    isMatched: false,
    value: 'red'
}, {
    isMatched: false,
    value: 'orange'
}];

// expected output

let a = [{
    isMatched: true,
    value: 'red'
} {
    isMatched: true,
    value: 'green'
}];
let b = [{
    isMatched: true,
    value: 'red'
}, {
    isMatched: false,
    value: 'brown'
}];
let c = [{
    isMatched: false,
    value: 'white'
}, {
    isMatched: true,
    value: 'green'
}];
let d = [{
    isMatched: true,
    value: 'red'
}, {
    isMatched: false,
    value: 'orange'
}];

yes all the 4 array needs to be compared with each other based on 'value' if match found need to update isMatched -> true — Surya
– Surya, Commented Oct 23, 2020 at 11:22

Nina Scholz · Accepted Answer · 2020-10-23 11:32:53Z

You could take a Map, check if the map contains a data set with value as key and if not add the object to the map or set the stored object's isMatched property to true, as well as the actual object.

For preventing setting true to much the value is changed to undefined.

let a = [{ isMatched: false, value: 'red' }, { isMatched: false, value: 'green' }],
    b = [{ isMatched: false, value: 'red' }, { isMatched: false, value: 'brown' }],
    c = [{ isMatched: false, value: 'white' }, { isMatched: false,  value: 'green' }],
    d = [{ isMatched: false, value: 'red' }, { isMatched: false, value: 'orange' }];

[a, b, c, d].forEach((m => a => a.forEach(o => {
    if (m.has(o.value)) {
        o.isMatched = true;
        const temp = m.get(o.value);
        if (temp) {
            temp.isMatched = true;
            m.set(o.value, undefined);
        }
    } else {
        m.set(o.value, o);
    }
}))(new Map));

console.log(a);
console.log(b);
console.log(c);
console.log(d);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Mo_- · Accepted Answer · 2020-10-23 11:37:32Z

0

You can combine all the arrays in one and then count the values that appear more than one:

let combinedArrays = a.concat(b, c, d);
countValues = {}

combinedArrays.forEach(function(v) {
  if (isNaN(countValues[v.value])) {
    countValues[v.value] = 1;
  }else {
    countValues[v.value] += 1;
  }
})

You can then iterate through each of the arrays and check if countValues[value] > 1 then set isMatched to true

answered Oct 23, 2020 at 11:37

Mo_-

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