Calling and addition function in python

Question

is there any way that I could add the string of one function by calling from other function.

def sumOfDoubleEvenPlace(number):
    sum += (getDigit(number))  # sum should be in this function

this is calling function.

def getDigit(number)-> int:
    sum = 0
    for i in range (len(number)-2, -1, -2):
        digit = int(number[i])
        digit = digit * 2
        if (digit >= 10):
        digit = (digit % 10) + 1
        #sum += digit   this is the result i want in the above function
    return digit

this function returns digit, and i want to add all the digits from get digit function into sum function. I commented the line, sum. So i want this sum in the first function. thanks for looking

Sounds like your method is misnamed then - Is that function doing something of any use? It seems to be doing a fairly arbitrary operation on the input, — CryptoFool
– CryptoFool, Commented Oct 25, 2020 at 3:23

avarice · Accepted Answer · 2020-10-25 03:24:37Z

1

Instead return the sum:

def getDigit(number)-> int:
    sum = 0
    for i in range (len(number)-2, -1, -2):
        digit = int(number[i])
        digit = digit * 2
        if (digit >= 10):
          digit = (digit % 10) + 1
          sum += digit
    
    return sum

In your case, we can yield digits first:

def getDigit(number)-> int:
    sum = 0
    for i in range (len(number)-2, -1, -2):
        digit = int(number[i])
        digit = digit * 2
        if (digit >= 10):
          digit = (digit % 10) + 1
          yield digit

And use for loop to calculate sum:

for x in getDigit(NUMBER):
  sum += x

edited Oct 25, 2020 at 3:24

answered Oct 25, 2020 at 3:14

avarice

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1 Comment

smith Over a year ago

yeah we can do that but the requirement is that sum should be done in the function above.

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