I am running multiple databases and I need to handle this exception. How can I do it either in the view or a more general approach ? I am using PostgreSQL. It's a bit ugly to wrap my whole code like below.
import psycopg2
def Main(request):
try:
myqs = customers.objects.all()
except psycopg2.OperationalError as e:
print('operational error, handle this')
return render(request, 'core/main/main.html', {'qs': myqs})
This is a more general solution. However I am not sure how to check which database the error occured. Any comments/ answers wouldd help
from django.db.utils import OperationalError
def db_operational_handler(func):
def inner_function(*args, **kwargs):
try:
func(*args, **kwargs)
except OperationalError:
return HttpResponse('Error Establishing a DB connection')
return inner_function
@db_operational_handler
def Main2(request):
myqs = customers.objects.all()
return render(request, 'core/main/main.html', {'qs': myqs})
Django has support for multiple databases, but this is more designed to allow partitioning of the application over multiple stores, like an authentication database and a content database. See Database routing.
I don't really see a good way to wrap failover at a single point in Django. I think this is a conscience choice by Django, as there are better suited tools for this at the database level itself, such as pgBouncer. There's a whole manual section dedicated to this topic. This solution would mean you have 1 connection to a loadbalancer that automatically selects from a pool of available servers.
