JavaScript sort array of objects on multiple properties by specific constant values

Question

Given an object like:

accounts = [
  { bankType: "Checking", currency: "USD", amount: 123.45 },
  { bankType: "Saving", currency: "CAD", amount: 1.95 },
  { bankType: "Saving", currency: "USD", amount: 23.31 },
  { bankType: "Checking", currency: "CAD", amount: 1953.1 },
];

How do I sort by the objects properties in the array where bankType of "Checkings" are sorted first then currency of "CAD" accounts are sorted next to achieve the following result below?

// Sorted array of objects result
[
  { bankType: "Checking", currency: "CAD", amount: 1953.1 },
  { bankType: "Checking", currency: "USD", amount: 123.45 },
  { bankType: "Saving", currency: "CAD", amount: 1.95 },
  { bankType: "Saving", currency: "USD", amount: 23.31 },
];

The problem isn't about sorting it alphabetically using the built-in localeCompare function, the problem lies in having to sort by specific constant value of Checking first then by CAD second.

Xhulian · Accepted Answer · 2020-11-13 03:49:31Z

3

With a point system

Checking = 2

CAD = 1

console.log(
    [
        { bankType: "Checking", currency: "USD", amount: 123.45 },
        { bankType: "Saving", currency: "CAD", amount: 1.95 },
        { bankType: "Saving", currency: "USD", amount: 23.31 },
        { bankType: "Checking", currency: "CAD", amount: 1953.1 },
    ]
        .sort((a, b) => {
            const pointsA = (a.bankType === "Checking" ? 2 : 0) + (a.currency === "CAD" ? 1 : 0);
            const pointsB = (b.bankType === "Checking" ? 2 : 0) + (b.currency === "CAD" ? 1 : 0);

            return pointsB - pointsA;
        })
);

edited Nov 13, 2020 at 3:49

answered Nov 13, 2020 at 3:02

Xhulian

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Comments

Aplet123 · Accepted Answer · 2020-11-13 02:15:17Z

3

You can just compare the two in order:

accounts.sort((a, b) =>
    a.bankType.localeCompare(b.bankType) || a.currency.localeCompare(b.currency)
);

answered Nov 13, 2020 at 2:15

Aplet123

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1 Comment

user1757703 Over a year ago

added clarity to the problem. my problem isn't being able to sort alphabetically by localeCompare, but by a constant value of Checking first then CAD.

Derek Wang · Accepted Answer · 2020-11-13 02:15:14Z

0

Using Array.prototype.sort and String.prototype.localeCompare, you can sort them.

const accounts = [
  { bankType: "Checking", currency: "USD", amount: 123.45 },
  { bankType: "Saving", currency: "CAD", amount: 1.95 },
  { bankType: "Saving", currency: "USD", amount: 23.31 },
  { bankType: "Checking", currency: "CAD", amount: 1953.1 },
];

const output = accounts.sort((a, b) => {
  const bankCompare = a.bankType.localeCompare(b.bankType);
  if (bankCompare === 0) {
    return a.currency.localeCompare(b.currency);
  }
  return bankCompare;
});
console.log(output);

answered Nov 13, 2020 at 2:15

Derek Wang

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1 Comment

user1757703 Over a year ago

Apologies for the confusion, added clarity to the problem. My problem isn't being able to sort alphabetically by localeCompare, but by a constant value of Checking first then CAD.

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