Php-Ajax-JS Multiple Data Returns Problem

Question

i have a problem.I am waiting for your help.Thank you

index codes are here.Even if i write dataType:JSON it didn't work.

index.php

function referansButon(sayfaNo)
       {
           $.ajax({
           url:"ajax.php",
           type:"POST",
                                   
           data:"action=referansButon&referansSayfano="+sayfaNo,
           success:function(data)
           {
               var result=$.parseJSON(data);
               alert(result[0]);
              alert(result["referanslar"]); // i know they are the same but i just wanted to see it if it 
                                          //is working
           }
                   
         });
      }

ajax.php

$referanslar="sdfdsfds";
$sayfalar= "sdfsdfdsfds";   //just for trying values.
$array=array("referanslar"=>$referanslar,"sayfalar"=>$sayfalar);
echo json_encode($array);

What is returning any thing or just null

The IRF
– The IRF

2020-11-13 15:11:03 +00:00
Commented Nov 13, 2020 at 15:11 — The IRF
– The IRF, Commented Nov 13, 2020 at 15:11
data variable is full but result variable is empty

İrfan Sağdıç
– İrfan Sağdıç

2020-11-13 15:18:33 +00:00
Commented Nov 13, 2020 at 15:18 — İrfan Sağdıç
– İrfan Sağdıç, Commented Nov 13, 2020 at 15:18
Your getting values with wrong ways

The IRF
– The IRF

2020-11-13 15:22:43 +00:00
Commented Nov 13, 2020 at 15:22 — The IRF
– The IRF, Commented Nov 13, 2020 at 15:22
And what kind of value is data?

Emiel Zuurbier
– Emiel Zuurbier

2020-11-13 15:24:04 +00:00
Commented Nov 13, 2020 at 15:24 — Emiel Zuurbier
– Emiel Zuurbier, Commented Nov 13, 2020 at 15:24
clear your self with the answer below

The IRF
– The IRF

2020-11-13 15:24:17 +00:00
Commented Nov 13, 2020 at 15:24 — The IRF
– The IRF, Commented Nov 13, 2020 at 15:24

The IRF · Accepted Answer · 2020-11-13 15:28:38Z

2

data is a string which is returning from $.ajax you convert the string to json and store in var result and after that you are using data again which is still string. update your code

var result=$.parseJSON(data);

and for first obj

alert(result.referanslar);

And for second obj

alert(result.sayfalar);

instead of [0] & [1]

answered Nov 13, 2020 at 15:28

The IRF

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1 Comment

İrfan Sağdıç Over a year ago

json could not be converted to string , i did what you trying to say but its same

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